zoukankan      html  css  js  c++  java
  • LeetCode 524. Longest Word in Dictionary through Deleting

    原题链接在这里:https://leetcode.com/problems/longest-word-in-dictionary-through-deleting/

    题目:

    Given a string and a string dictionary, find the longest string in the dictionary that can be formed by deleting some characters of the given string. If there are more than one possible results, return the longest word with the smallest lexicographical order. If there is no possible result, return the empty string.

    Example 1:

    Input:
    s = "abpcplea", d = ["ale","apple","monkey","plea"]
    
    Output: 
    "apple"

    Example 2:

    Input:
    s = "abpcplea", d = ["a","b","c"]
    
    Output: 
    "a"

    Note:

    1. All the strings in the input will only contain lower-case letters.
    2. The size of the dictionary won't exceed 1,000.
    3. The length of all the strings in the input won't exceed 1,000.

    题解:

    For each word in the string dictionary, try to compare it with s. If there is a char in s matching current pointed char in word, move the index. 

    If the index could move to end of word, it means word could be formed by deleting some characters of s.

    Then update res based on length lexicographical order of word.

    Time Complexity: O(m*n). m = s.length(). n = d.size().

    Space: O(1). regardless res.

    AC Java:

     1 class Solution {
     2     public String findLongestWord(String s, List<String> d) {
     3         if(s == null || d == null || d.size() == 0){
     4             return "";
     5         }
     6         
     7         String res = "";
     8         for(String word : d){
     9             int i = 0;
    10             for(char c : s.toCharArray()){
    11                 if(i<word.length() && c == word.charAt(i)){
    12                     i++;
    13                 }
    14             }
    15             
    16             if(i == word.length()){
    17                 if(res.length() < word.length()){
    18                     res = word;
    19                 }else if(res.length() == word.length() && res.compareTo(word)>0){
    20                     res = word;
    21                 }
    22             }
    23         }
    24         
    25         return res;
    26     }
    27 }
  • 相关阅读:
    qq客服不需要加好友
    mysql中表名为关键字的处理方法
    DIV+CSS最小高度(兼容IE6\IE7\FF)(转载)
    Js%26String添加加+trim()方法
    MS Sql 定期自动备份
    MySQL 中文显示乱码
    SQL Server 2005 中的Row_Number()函数
    Jquery中使用setInterval和setTimeout
    fieldset 居中
    script language="JavaScript" defer
  • 原文地址:https://www.cnblogs.com/Dylan-Java-NYC/p/11403312.html
Copyright © 2011-2022 走看看