zoukankan      html  css  js  c++  java
  • LeetCode 524. Longest Word in Dictionary through Deleting

    原题链接在这里:https://leetcode.com/problems/longest-word-in-dictionary-through-deleting/

    题目:

    Given a string and a string dictionary, find the longest string in the dictionary that can be formed by deleting some characters of the given string. If there are more than one possible results, return the longest word with the smallest lexicographical order. If there is no possible result, return the empty string.

    Example 1:

    Input:
    s = "abpcplea", d = ["ale","apple","monkey","plea"]
    
    Output: 
    "apple"

    Example 2:

    Input:
    s = "abpcplea", d = ["a","b","c"]
    
    Output: 
    "a"

    Note:

    1. All the strings in the input will only contain lower-case letters.
    2. The size of the dictionary won't exceed 1,000.
    3. The length of all the strings in the input won't exceed 1,000.

    题解:

    For each word in the string dictionary, try to compare it with s. If there is a char in s matching current pointed char in word, move the index. 

    If the index could move to end of word, it means word could be formed by deleting some characters of s.

    Then update res based on length lexicographical order of word.

    Time Complexity: O(m*n). m = s.length(). n = d.size().

    Space: O(1). regardless res.

    AC Java:

     1 class Solution {
     2     public String findLongestWord(String s, List<String> d) {
     3         if(s == null || d == null || d.size() == 0){
     4             return "";
     5         }
     6         
     7         String res = "";
     8         for(String word : d){
     9             int i = 0;
    10             for(char c : s.toCharArray()){
    11                 if(i<word.length() && c == word.charAt(i)){
    12                     i++;
    13                 }
    14             }
    15             
    16             if(i == word.length()){
    17                 if(res.length() < word.length()){
    18                     res = word;
    19                 }else if(res.length() == word.length() && res.compareTo(word)>0){
    20                     res = word;
    21                 }
    22             }
    23         }
    24         
    25         return res;
    26     }
    27 }
  • 相关阅读:
    第四课:数字系统抽象
    第三课:叠加法和戴维南法
    第二课:基本电路法
    电路和电子学第一课:集总电路抽象
    第三十六课:告别演出
    第三十五课:多普勒效应和宇宙大爆炸
    第三十四课:光栅和分辨率
    第三十三课:干涉
    第三十二课:复习课
    第三十一集:彩虹
  • 原文地址:https://www.cnblogs.com/Dylan-Java-NYC/p/11403312.html
Copyright © 2011-2022 走看看