zoukankan      html  css  js  c++  java
  • 如何获得数据库中所有用户创建的索引

    Requirement

    今天遇到一个SQL Performance Tuning需求:

    对于用户表的索引进行优化,剔出那些重复的索引,添加必要的索引。

    那么,我们必须先把表中的索引给找出来,SQL Server数据库和其他数据库一样,都有强大的元数据表,所以我们也可以从元数据表中得到索引(INDEX)的信息。 要完成这个查询需求,会涉及到master数据库中的几个视图(VIEW):

    • sys.[indexes]
    • sys.[index_columns]
    • sys.[all_columns]
    • sys.[tables]
    • sys.[schemas]

    Resolution

    SELECT '['+Sch.name+'].['+ Tab.[name]+']' AS TableName, 
           Ind.[name] AS IndexName, 
           SUBSTRING(( SELECT ', ' + AC.name 
                         FROM sys.[tables] AS T 
                        INNER JOIN sys.[indexes] I 
                           ON T.[object_id] = I.[object_id] 
                        INNER JOIN sys.[index_columns] IC 
                           ON I.[object_id] = IC.[object_id] 
                          AND I.[index_id] = IC.[index_id] 
                        INNER JOIN sys.[all_columns] AC 
                           ON T.[object_id] = AC.[object_id] 
                          AND IC.[column_id] = AC.[column_id] 
                        WHERE Ind.[object_id] = I.[object_id] 
                          AND Ind.index_id = I.index_id 
                          AND IC.is_included_column = 0 
                        ORDER BY IC.key_ordinal 
                          FOR XML PATH('') 
                     ), 2, 8000) AS KeyColumns, 
           SUBSTRING(( SELECT ', ' + AC.name 
                         FROM sys.[tables] AS T 
                        INNER JOIN sys.[indexes] I 
                           ON T.[object_id] = I.[object_id] 
                        INNER JOIN sys.[index_columns] IC 
                           ON I.[object_id] = IC.[object_id] 
                          AND I.[index_id] = IC.[index_id] 
                        INNER JOIN sys.[all_columns] AC 
                           ON T.[object_id] = AC.[object_id] 
                          AND IC.[column_id] = AC.[column_id] 
                        WHERE Ind.[object_id] = I.[object_id] 
                          AND Ind.index_id = I.index_id 
                          AND IC.is_included_column = 1 
                        ORDER BY IC.key_ordinal 
                          FOR XML PATH('') 
                     ), 2, 8000) AS IncludedColumns,
           Ind.type_desc AS IndexType,
           CASE Ind.is_primary_key
               WHEN 0 THEN 'N'
               WHEN 1 THEN 'Y'
           END AS IsPrimaryKey,
           CASE Ind.is_unique
               WHEN 0 THEN 'N'
               WHEN 1 THEN 'Y'
           END AS IsUnique
      FROM sys.[indexes] Ind 
     INNER JOIN sys.[tables] AS Tab 
        ON Tab.[object_id] = Ind.[object_id] 
     INNER JOIN sys.[schemas] AS Sch 
        ON Sch.[schema_id] = Tab.[schema_id] 
     WHERE Ind.[name] is not null
     ORDER BY TableName DESC
    

    Explanation

    上边这段代码的难点可能就是FOR XML PATH的用法。可以参考下面这篇博文:

    Examples

    在此我们拿Northwind数据库来演示代码执行后的结果。

    TableName IndexName KeyColumns IncludeColumns IndexType IsPrimaryKey IsUnique
    [dbo].[Territories] PK_Territories TerritoryID NULL NONCLUSTERED Y Y
    [dbo].[Suppliers] PK_Suppliers SupplierID NULL CLUSTERED Y Y
    [dbo].[Suppliers] CompanyName CompanyName NULL NONCLUSTERED N N
    [dbo].[Suppliers] PostalCode PostalCode NULL NONCLUSTERED N N
    [dbo].[Shippers] PK_Shippers ShipperID NULL CLUSTERED Y Y
    [dbo].[Region] PK_Region RegionID NULL NONCLUSTERED Y Y
    [dbo].[Products] PK_Products ProductID NULL CLUSTERED Y Y
    [dbo].[Products] CategoriesProducts CategoryID NULL NONCLUSTERED N N
  • 相关阅读:
    NOI2017 游戏
    2-SAT问题的方案输出
    hdu 2433 Travel
    bzoj千题计划230:bzoj3205: [Apio2013]机器人
    bzoj千题计划229:bzoj4424: Cf19E Fairy
    hdu 6166 Senior Pan
    poj 2404 Jogging Trails
    Oracle 删除数据后释放数据文件所占磁盘空间
    安装LINUX X86-64的10201出现链接ins_ctx.mk错误
    10G之后统计信息收集后为什么执行计划不会被立马淘汰
  • 原文地址:https://www.cnblogs.com/EasonWu/p/get-all-user-defined-index.html
Copyright © 2011-2022 走看看