这个是一个很简单很明显的线段树的区间合并,不过区间合并的题目都还是有点难写,建议存个板子。
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#include <cstdio> #include <cstdlib> #include <algorithm> #include <iostream> #define inf 0x3f3f3f3f using namespace std; const int maxn = 1e5 + 100; struct node { int l, r, rp, lp, len; int max_pre, max_sub, max_last; }tree[maxn*4]; int a[maxn]; void push_up(int id) { tree[id].rp = tree[id<<1|1].rp; tree[id].lp = tree[id << 1].lp; tree[id].max_pre = tree[id << 1].max_pre; tree[id].max_last = tree[id << 1 | 1].max_last; tree[id].max_sub = max(tree[id << 1].max_sub, tree[id << 1 | 1].max_sub); if(tree[id<<1].rp<tree[id<<1|1].lp) { if (tree[id << 1].max_pre == tree[id << 1].len) tree[id].max_pre += tree[id << 1 | 1].max_pre; if (tree[id << 1 | 1].max_last == tree[id << 1 | 1].len) tree[id].max_last += tree[id << 1].max_last; tree[id].max_sub = max(tree[id].max_sub, tree[id << 1].max_last + tree[id<<1|1].max_pre); } } void build(int id,int l,int r) { tree[id].l = l; tree[id].r = r; tree[id].len = r - l + 1; if(l==r) { tree[id].rp = tree[id].lp = a[l]; tree[id].max_pre = tree[id].max_last = tree[id].max_sub = 1; return; } int mid = (l+r) >> 1; build(id << 1, l, mid); build(id << 1 | 1, mid + 1, r); push_up(id); } int query(int id,int x,int y) { int ans = 0; if(x<=tree[id].l&&tree[id].r<=y) { return tree[id].max_sub; } int mid = (tree[id].l + tree[id].r) >> 1; if (x <= mid) ans = max(ans, query(id << 1, x, y)); if (y > mid) ans = max(ans, query(id << 1 | 1, x, y)); if(tree[id<<1].rp<tree[id<<1|1].lp) { ans = max(ans, min(mid - x + 1, tree[id << 1].max_last) + min(y - mid, tree[id << 1 | 1].max_pre)); } return ans; } void update(int id,int x,int z) { if(tree[id].l==tree[id].r&&tree[id].l==x) { tree[id].rp = z; tree[id].lp = z; return; } int mid = (tree[id].l + tree[id].r) >> 1; if (x <= mid) update(id << 1, x, z); if (x > mid) update(id << 1 | 1, x, z); push_up(id); } int main() { int t; scanf("%d", &t); while(t--) { int n, m; scanf("%d%d", &n, &m); for(int i=1;i<=n;i++) { scanf("%d", &a[i]); } build(1, 1, n); while(m--) { char s[10]; int x, y; scanf("%s %d %d", s, &x, &y); if(s[0]=='Q') { int ans = query(1, x+1, y+1); printf("%d ", ans); } else update(1, x+1, y); } } }