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  • 线段树的区间合并 B

     这个是一个很简单很明显的线段树的区间合并,不过区间合并的题目都还是有点难写,建议存个板子。

    #include <cstdio>
    #include <cstdlib>
    #include <algorithm>
    #include <iostream>
    #define inf 0x3f3f3f3f
    using namespace std;
    const int maxn = 1e5 + 100;
    struct node
    {
        int l, r, rp, lp, len;
        int max_pre, max_sub, max_last;
    }tree[maxn*4];
    int a[maxn];
    
    void push_up(int id)
    {
        tree[id].rp = tree[id<<1|1].rp;
        tree[id].lp = tree[id << 1].lp;
        tree[id].max_pre = tree[id << 1].max_pre;
        tree[id].max_last = tree[id << 1 | 1].max_last;
        tree[id].max_sub = max(tree[id << 1].max_sub, tree[id << 1 | 1].max_sub);
        if(tree[id<<1].rp<tree[id<<1|1].lp)
        {
            if (tree[id << 1].max_pre == tree[id << 1].len) tree[id].max_pre += tree[id << 1 | 1].max_pre;
            if (tree[id << 1 | 1].max_last == tree[id << 1 | 1].len) tree[id].max_last += tree[id << 1].max_last;
            tree[id].max_sub = max(tree[id].max_sub, tree[id << 1].max_last + tree[id<<1|1].max_pre);
        }
    }
    
    void build(int id,int l,int r)
    {
        tree[id].l = l;
        tree[id].r = r;
        tree[id].len = r - l + 1;
        if(l==r)
        {
            tree[id].rp = tree[id].lp = a[l];
            tree[id].max_pre = tree[id].max_last = tree[id].max_sub = 1;
            return;
        }
        int mid = (l+r) >> 1;
        build(id << 1, l, mid);
        build(id << 1 | 1, mid + 1, r);
        push_up(id);
    }
    
    int query(int id,int x,int y)
    {
        int ans = 0;
        if(x<=tree[id].l&&tree[id].r<=y)
        {
            return tree[id].max_sub;
        }
        int mid = (tree[id].l + tree[id].r) >> 1;
        if (x <= mid) ans = max(ans, query(id << 1, x, y));
        if (y > mid) ans = max(ans, query(id << 1 | 1, x, y));
        if(tree[id<<1].rp<tree[id<<1|1].lp)
        {
            ans = max(ans, min(mid - x + 1, tree[id << 1].max_last) + min(y - mid, tree[id << 1 | 1].max_pre));
        }
        return ans;
    }
    
    void update(int id,int x,int z)
    {
        if(tree[id].l==tree[id].r&&tree[id].l==x)
        {
            tree[id].rp = z;
            tree[id].lp = z;
            return;
        }
        int mid = (tree[id].l + tree[id].r) >> 1;
        if (x <= mid) update(id << 1, x, z);
        if (x > mid) update(id << 1 | 1, x, z);
        push_up(id);
    }
    
    int main()
    {
        int t;
        scanf("%d", &t);
        while(t--)
        {
            int n, m;
            scanf("%d%d", &n, &m);
            for(int i=1;i<=n;i++)
            {
                scanf("%d", &a[i]);
            }
            build(1, 1, n);
            while(m--)
            {
                char s[10];
                int x, y;
                scanf("%s %d %d", s, &x, &y);
                if(s[0]=='Q')
                {
                    int ans = query(1, x+1, y+1);
                    printf("%d
    ", ans);
                }
                else update(1, x+1, y);
            }
        }
    }
    View Code
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  • 原文地址:https://www.cnblogs.com/EchoZQN/p/10804394.html
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