hdu1318

很繁琐，花了将近两个小时。。。。。。。

#include"iostream"
using namespace std;
int main()
{
    char a[100];
    int i,j,L;
    while(scanf("%s",a)!=EOF)
    {
         L=strlen(a);
        
           int num=0,zf=0,sign=0;          
         for(i=0;i<L;i++)
         {
            if(a[i]>='0'&&a[i]<='9') {  num=1;}
            if(a[i]>='A'&&a[i]<='Z') {  zf=1; }
            if(a[i]=='O'||a[i]=='0') { sign=1;}
         }
        
        int count=0,mark=0;

        if(L==1)  //单独处理只有一个的情况
         {
                if(a[0]=='8'||a[0]=='0'||a[0]=='1') { mark++;}
                 if(a[0]>='T'&&a[0]<='Y')
                 {
                      mark++;
                }
                if(a[0] == 'H' || a[0] == 'I'||a[0]=='M'|| a[0]=='A'||a[0]=='O')
                {
                     mark++; 
                }
                if(a[0]=='2'||a[0]=='S'||a[0]=='5'||a[0]=='Z'||a[0]=='3'||a[0]=='E') count++;
                    printf("%s -- ",a);
                  if(mark==1) printf("is a mirrored palindrome.\n"); 
                     else  if(mark==0&&count==1)  printf("is a mirrored string.\n");
                           else   printf("is a regular palindrome.\n"); 

        }
        else
        {
        if(num==1&&zf==1)
        {
        for( i=0, j=L-1; j>=L/2+1 , i<L/2;  j--, i++)
        {

            if(a[i]>='A'&&a[i]<='Z')//处理字母的情况
            {
                
                if(a[i]>='T'&&a[i]<='Y')
                {
                    if(a[i]==a[j]) { count++; mark++;}
                }
                else if(a[i] == 'H' || a[i] == 'I'||a[i]=='M'|| a[i]=='A')
                {
                    if(a[i] == a[j]) {  count++; mark++; }
                }
                else if( (a[i] == 'J'&&(a[j] == 'L'||a[j]=='J'))||(a[i]=='L'&&(a[j]=='J'||
              a[j]=='L')) ) count++;
                else if( (a[i]=='E'&&(a[j]=='3'||a[j]=='E')) || (a[i]=='O'&&(a[j]=='0'
                  ||a[j]=='O'))||(a[i]=='Z'&&(a[j]=='5'||a[j]=='Z'))||
               (a[i]=='S'&&(a[j]=='2'||a[j]=='S' ))) count++;
            }
            else if(a[i]>='0'&&a[i]<='9') //处理数字的情况
            {
                 
                  if((a[i]=='8'&&a[j]=='8')||(a[i]=='0'&&a[j]=='0')||(a[i]=='1'&&a[j]=='1'))
                 { mark++;}
                  if((a[i]=='2'&&(a[j]=='S'||a[j]=='2'))||(a[i]=='5'&&(a[j]=='Z'||a[j]=='5'))
    ||(a[i]=='3'&&(a[j]=='E'||a[j]=='3'))||(a[i]=='0'&&(a[j]=='0'||a[j]=='O'))) count++;
                     
                  else 
                  {
                      if(a[i]==a[j]) count++;
                  }     
            }
        }
        }
        else 
        {
            for( i=0, j=L-1; j>=L/2+1 , i<L/2;  j--, i++)
            {
                if(a[i]==a[j]) count++;
                 if((a[i]=='8'&&a[j]=='8')||(a[i]=='0'&&a[j]=='0')||(a[i]=='1'&&a[j]=='1'))
                   { mark++;}
                 if(a[i]>='T'&&a[i]<='Y')
                 {
                    if(a[i]==a[j]) {  mark++;}
                }
                if(a[i] == 'H' || a[i] == 'I'||a[i]=='M'|| a[i]=='A'||a[i]=='O')
                {
                    if(a[i] == a[j]) { mark++; }
                }
            }
        }
        
        printf("%s -- ",a);
        if(count==L/2)
        {
             if(mark==L/2) printf("is a mirrored palindrome.\n"); 
               else if(num==1&&zf==1)    printf("is a mirrored string.\n");
                   else if(num==0||zf==0)  printf("is a regular palindrome.\n");  
        }
         else printf("is not a palindrome.\n");
        }
         printf("\n");
    }
    return 0;
}