A + B Again
Time Limit: 1000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 12317 Accepted Submission(s): 5387
Problem Description
There must be many A + B problems in our HDOJ , now a new one is coming. Give you two hexadecimal integers , your task is to calculate the sum of them,and print it in hexadecimal too. Easy ? AC it !
Input
The input contains several test cases, please process to the end of the file. Each case consists of two hexadecimal integers A and B in a line seperated by a blank. The length of A and B is less than 15.
Output
For each test case,print the sum of A and B in hexadecimal in one line.
Sample Input
+A -A
+1A 12
1A -9
-1A -12
1A -AA
Sample Output
0
2C
11
-2C
-90
Author
linle
Source
Recommend
linle
代码:
#include<stdio.h> #include<iostream> #include<iomanip> using namespace std; int main() { __int64 a, b; while(scanf("%I64X%I64X",&a,&b)!=EOF) { __int64 sum =a + b; if(sum < 0) { sum =- sum; printf("-"); } printf("%I64X ",sum); } }