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  • leetcode Valid Sudoku

    题目连接

    https://leetcode.com/problems/valid-sudoku/ 

    Valid Sudoku

    Description

    Determine if a Sudoku is valid, according to: Sudoku Puzzles - The Rules.

    The Sudoku board could be partially filled, where empty cells are filled with the character '.'.

    A partially filled sudoku which is valid.

    Note:
    A valid Sudoku board (partially filled) is not necessarily solvable. Only the filled cells need to be validated.

    直接判断。。

    class Solution {
    public:
    	static const int N = 9;
    	bool isValidSudoku(vector<vector<char>>& board) {
    		for (int i = 0; i < N; i++) {
    			for (int j = 0; j < N; j++) {
    				if (board[i][j] == '.') continue;
    				if (!isOk(board, i, j, board[i][j])) return false;
    			}
    		}
    		return true;
    	}
    	bool isOk(vector<vector<char>>& board, int x,int y,char ch) {
    		int vis[3][N + 1] = { 0 };
    		for (int i = 0; i < N; i++) {
    			if (board[x][i] != '.') {
    				vis[0][board[x][i] - '0']++;
    			}
    			if (board[i][y] != '.') {
    				vis[1][board[i][y] - '0']++;
    			}
    		}
    		for (int i = x / 3 * 3; i <= x / 3 * 3 + 2; i++) {
    			for (int j = y / 3 * 3; j <= y / 3 * 3 + 2; j++) {
    				if (board[i][j] != '.') {
    					vis[2][board[i][j] - '0']++;
    				}
    			}
    		}
    		for (int i = 1; i <= N; i++) {
    			if (vis[0][i] > 1 || vis[1][i] > 1 || vis[2][i] > 1) return false;
    		}
    		return true;
    	}
    };
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  • 原文地址:https://www.cnblogs.com/GadyPu/p/5040179.html
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