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  • [八省联考2018]林克卡特树lct

    #include<bits/stdc++.h>
    #define RG register
    #define IL inline
    #define _ 500005
    #define INF 1e18
    #define ll long long
    using namespace std;
    
    IL ll gi(){
        RG ll data = 0 , m = 1; RG char ch = 0;
        while(ch != '-' && (ch<'0' || ch > '9')) ch = getchar();
        if(ch == '-'){m = 0; ch = getchar();}
        while(ch>='0' && ch<='9'){data = (data<<1) + (data<<3) + ch - '0' ;  ch = getchar();}
        return (m) ? data : -data ; 
    }
    
    struct DP{
        ll v , cnt ; 
        IL DP(){cnt = v = 0 ; }
        IL DP(RG ll a , RG ll b){v = a ; cnt = b ; }
        IL void mem(){cnt = v = 0 ; }
        DP operator + (RG DP &B){return DP(v + B.v , cnt + B.cnt) ; }
        DP operator + (RG ll &B){return DP(v + B , cnt) ; }
        DP operator * (RG DP &B){return DP(v + B.v , cnt + B.cnt - 1) ; }
    }f[_][3],Ans[_],tmp; 
    IL DP Max(RG DP A , RG DP B){
        if(A.v ^ B.v) return (A.v < B.v) ? B : A ; 
        else return (A.cnt < B.cnt) ? B : A ;  
    }
    ll n,K,L,R,C,Ret,head[_]; struct Edge{ll to,next,w;}t[_<<2] ; ll oo ;  
    
    IL void add(RG ll u,RG ll v,RG ll w){
        t[++oo] = (Edge){v , head[u] , w} ; head[u] = oo ; 
        t[++oo] = (Edge){u , head[v] , w} ; head[v] = oo ; 
    }
    
    void dfs(RG ll u,RG ll From){
        f[u][0] = (DP){0 , 0} ; Ans[u] = (DP){-INF , 0} ; 
        f[u][1] = (DP){-C , 1} ; f[u][2] = (DP){-INF , 0} ;  
        for(RG ll i = head[u] ; i ; i = t[i].next){
            RG ll v = t[i].to ; if(v == From) continue ; 
            dfs(v , u) ; 
            f[u][2] = Max(f[u][2] , f[u][2] + Ans[v]) ; 
            f[u][2] = Max(f[u][2] , (f[u][1] * f[v][1]) + t[i].w + C) ;
            tmp = f[u][0] + f[v][0]; C = -C ; tmp = tmp + t[i].w + C; C = -C ; tmp.cnt ++ ; 
            f[u][1] = Max(f[u][1] , f[u][1] + Ans[v]) ; 
            f[u][1] = Max(f[u][1] , Max(f[u][0] + f[v][1] + t[i].w , tmp)) ; 
            f[u][0] = Max(f[u][0] , f[u][0] + Ans[v]) ;
        } 
        Ans[u] = Max(Max(f[u][0] , f[u][1]) , f[u][2]) ; return ; 
    }
    
    int main(){
        n = gi() ; K = gi() ; 
        for(RG ll i = 1,u,v,w; i < n; i ++)
            u = gi() , v = gi() , w = gi() , add(u , v , w) , R = R + abs(w);
        ++ K ;  L = -R ; 
        while(L <= R){
            C = (L + R) >> 1 ;		 
            dfs(1 , 0) ; 
            if(Ans[1].cnt <= K) Ret = C , R = C - 1 ; 
            else L = C + 1; 		
        }
        C = Ret ; dfs(1 , 0) ;  
        printf("%lld
    " , Ans[1].v + Ret * Ans[1].cnt) ; return 0 ;	    
    }
    
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  • 原文地址:https://www.cnblogs.com/Guess2/p/9051429.html
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