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  • AutoCad .Net二次开发求两曲线最小距离

    测试结果:

    主要思路:假设有两条曲线分别是c1和c2,把c1按照1的距离划分我这里用变量jd表示,得到一个曲线集合coll,然后遍历coll,得到coll中每一个曲线的两个端点,再用这两个端点分别求离曲线c2的最短距离,直接使用开发库的GetClosestPointTo方法就可以了,直到遍历完整个coll集合就能得到最短距离和其对应的点。

    主要代码得到曲线集合coll:

     public List<Curve> GetCurves(Curve curve ,double jd)
            {
                List<Curve> lstCurves = new List<Curve>();
    
                double totalLength = curve.GetDistanceAtParameter(curve.EndParam);
    
                if (totalLength < jd)
                {
                    lstCurves.Add(curve);
                    return lstCurves;
                }
                double addLength = 0;
    
                Point3dCollection pt3dCol = new Point3dCollection();
    
                while (addLength < totalLength)
                {
                    pt3dCol.Add(curve.GetPointAtDist(addLength));
                    addLength += jd;
    
                }
                if (addLength != totalLength)
                    pt3dCol.Add(curve.GetPointAtDist(totalLength));
    
    
               DBObjectCollection dbObjColl= curve.GetSplitCurves(pt3dCol);
    
                foreach (var item in dbObjColl)
                {
                    lstCurves.Add((Curve)item);
                }
    
                dbObjColl.Dispose();
    
                return lstCurves;
            }
    View Code

    主要代码得到最短距离和最近点:

    public Line GetMinLine(Curve curve1,Curve curve2,double jd)
            {
                List<Curve> lstCurves = GetCurves(curve1, jd);
    
                double minVal = double.MaxValue;
                Point3d ptMin1 = Point3d.Origin;
                Point3d ptMin2 = Point3d.Origin;
                foreach (var c in lstCurves)
                {
                    Point3d pt1 = c.StartPoint;
                    Point3d pt2 = c.EndPoint;
    
                    var pt11=curve2.GetClosestPointTo(pt1, false);
                    var pt22= curve2.GetClosestPointTo(pt2, false);
    
                    var l1 = pt11.DistanceTo(pt1);
                    var l2 = pt22.DistanceTo(pt2);
    
                    if (l1 < minVal)
                    {
                        minVal = l1;
                        ptMin1 = pt11;
                        ptMin2 = pt1;
                    }
                    if (l2 < minVal)
                    {
                        minVal = l2;
                        ptMin1 = pt22;
                        ptMin2 = pt2;
                    }
    
                }
                ed.WriteMessage("
    最短距离:" + minVal + "
    ");
    
                return new Line(ptMin1,ptMin2);
            }
    View Code

    关于GetClosestPointTo介绍如下:

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  • 原文地址:https://www.cnblogs.com/HelloQLQ/p/12112982.html
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