zoukankan      html  css  js  c++  java
  • uva1587 Box

    Ivan works at a factory that produces heavy machinery. He has a simple job -- he knocks up wooden boxes of different sizes to pack machinery for delivery to the customers. Each box is a rectangular parallelepiped. Ivan uses six rectangular wooden pallets to make a box. Each pallet is used for one side of the box.

    epsfbox{p3214.eps}

    Joe delivers pallets for Ivan. Joe is not very smart and often makes mistakes -- he brings Ivan pallets that do not fit together to make a box. But Joe does not trust Ivan. It always takes a lot of time to explain Joe that he has made a mistake. Fortunately, Joe adores everything related to computers and sincerely believes that computers never make mistakes. Ivan has decided to use this for his own advantage. Ivan asks you to write a program that given sizes of six rectangular pallets tells whether it is possible to make a box out of them.

    Input 

    Input file contains several test cases. Each of them consists of six lines. Each line describes one pallet and contains two integer numbersw and h ( 1$ le$wh$ le$10 000) -- width and height of the pallet in millimeters respectively.

    Output 

    For each test case, print one output line. Write a single word ` POSSIBLE' to the output file if it is possible to make a box using six given pallets for its sides. Write a single word ` IMPOSSIBLE' if it is not possible to do so.

    Sample Input 

    1345 2584
    2584 683
    2584 1345
    683 1345
    683 1345
    2584 683
    1234 4567
    1234 4567
    4567 4321
    4322 4567
    4321 1234
    4321 1234
    

    Sample Output 

    POSSIBLE
    IMPOSSIBLE

    希望每次代码都有进步。
    AC代码:
     1 #include<iostream>
     2 
     3 using namespace std;
     4 
     5 
     6 struct Box
     7 {
     8     int a,b;
     9 } box[6];
    10 
    11 
    12 void Swap(int *,int *);
    13 void Sort();
    14 int Judge();
    15 
    16 
    17 int main()
    18 {
    19     while(cin >> box[0].a >> box[0].b)
    20     {
    21         if(box[0].a<box[0].b)
    22             Swap(&box[0].a,&box[0].b);
    23         for(int i=1; i<6; i++)
    24         {
    25             cin >> box[i].a >> box[i].b;
    26             if(box[i].a<box[i].b)
    27                 Swap(&box[i].a,&box[i].b);
    28         }
    29         Sort();
    30         if(Judge())
    31             cout << "POSSIBLE" << endl;
    32         else
    33             cout << "IMPOSSIBLE" << endl;
    34     }
    35     return 0;
    36 }
    37 void Swap(int *p,int *q)
    38 {
    39     int r;
    40     r=*p;
    41     *p=*q;
    42     *q=r;
    43 }
    44 
    45 void Sort()
    46 {
    47     struct Box c;
    48     for(int i=1; i<6; i++)
    49         for(int j=0; j<6-i; j++)
    50         {
    51             if(box[j].a<box[j+1].a)
    52             {
    53                 c=box[j];
    54                 box[j]=box[j+1];
    55                 box[j+1]=c;
    56             }
    57         }
    58     for(int i=1; i<6; i++)
    59         for(int j=0; j<6-i; j++)
    60         {
    61             if(box[j].b<box[j+1].b&&box[j].a==box[j+1].a)
    62             {
    63                 c=box[j];
    64                 box[j]=box[j+1];
    65                 box[j+1]=c;
    66             }
    67         }
    68 }
    69 
    70 int Judge()
    71 {
    72     if(box[0].a==box[1].a&&box[1].a==box[2].a&&box[2].a==box[3].a)
    73         if(box[0].b==box[1].b&&box[1].b==box[4].a&&box[4].a==box[5].a)
    74             if(box[2].b==box[3].b&&box[3].b==box[4].b&&box[4].b==box[5].b)
    75                 return 1;
    76     return 0;
    77 }
    View Code
  • 相关阅读:
    人的一生为什么要努力 &1
    数据库_数据库系统概论
    电子商务安全
    虚拟专用网技术
    人的一生为什么要努力
    数据备份与恢复技术
    入侵检测技术
    简历模板连接
    防火墙技术
    字节与位
  • 原文地址:https://www.cnblogs.com/I-love-HLD/p/4204058.html
Copyright © 2011-2022 走看看