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  • POJ 1562 Oil Deposits

    简单DFS,搜索八个方向。

    # include <stdio.h>
    
    const int dir[][2] = {{-1,0}, {0,-1}, {0,1}, {1,0}, {1,1}, {1,-1}, {-1,1}, {-1,-1}};
    
    int n, m;
    char f[105][105];
    
    char read_data(void)
    {
        int i, j;
        
        scanf("%d", &m);
        scanf("%d", &n);
        if (m == 0) return 0;
        for (i = 1; i <= m; ++i)
        {
            scanf("%s", f[i]+1);
        }
        
        return 1;
    }
    
    void dfs(int ci, int cj)
    {
        int i, ni, nj;
        
        f[ci][cj] = '*';
        for (i = 0; i < 8; ++i)
        {
            ni = ci + dir[i][0];
            nj = cj + dir[i][1];
            if (1<=ni && ni<=m && 1<=nj && nj<=n && f[ni][nj]=='@')
            {
                dfs(ni, nj);
            }    
        }
    }
    
    void solve(void)
    {
        int cnt, i, j;
        
        cnt = 0;
        for (i = 1; i <= m; ++i)
        for (j = 1; j <= n; ++j)
        {
            if (f[i][j] == '@')
            {
                dfs(i, j);
                ++cnt;
            }
        }
        
        printf("%d\n", cnt);
    }
    
    int main()
    {
        while (read_data() == 1)
        {
            solve();
        }
        
        return 0;
    }
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  • 原文地址:https://www.cnblogs.com/JMDWQ/p/2534429.html
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