这道题的剪枝:奇偶性,曼哈顿距离类型的。不剪会超时。
# include <cstdio> # include <cstring> using namespace std; # define N 7 + 3 # define ABS(x) (((x)>0)?(x):(-(x))) int si, sj, gi, gj; int n, m, T; char g[N][N]; bool vis[N][N]; bool finished; const int dir[][2] = {{0,1}, {1,0}, {0,-1}, {-1,0}}; void dfs(int x, int y, int t) { int tmp = ABS(x-gi)+ABS(y-gj); if (tmp > t) return; if (tmp%2 != t%2) return ; if (t == 0) finished = (x == gi && y == gj); else for (int d = 0; d < 4; ++d) { int nx = x + dir[d][0], ny = y + dir[d][1]; if (1<=nx&&nx<=n && 1<=ny&&ny<=m && g[x][y]!='X' && vis[nx][ny]==false) { vis[nx][ny] = true; dfs(nx, ny, t-1); if (finished) return ; vis[nx][ny] = false; } } } void init(void) { int in; in = 0; for (int i = 1; i <= n; ++i) { scanf("%s", g[i]+1); memset(vis[i], false, sizeof(vis[0][0])*(m+1)); for (int j = 1; in<2 && j <= m; ++j) if(g[i][j] == 'S') si = i, sj = j, ++in; else if (g[i][j] == 'D') gi = i, gj = j, ++in; } } void solve(void) { finished = false; vis[si][sj] = true, dfs(si, sj, T); puts(finished ? "YES":"NO"); } int main() { while (scanf("%d%d%d", &n, &m, &T), n || m || T) { init(); solve(); } return 0; }
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