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  • LeetCode: Single Number Ⅱ

     1 /**
     2  * 
     3  */
     4 package solution;
     5 
     6 import java.util.Arrays;
     7 
     8 /**
     9  * @author whh
    10  * 
    11  *         Given an array of integers, every element appears three times except
    12  *         for one. Find that single one.
    13  * 
    14  *         Note: Your algorithm should have a linear runtime complexity. Could
    15  *         you implement it without using extra memory?
    16  */
    17 public class SingleNumber2 {
    18 
    19     /**
    20      * @param args
    21      */
    22     public static void main(String[] args) {
    23         int[] A1 = { 1 };
    24         int[] A2 = { 1, 2, 3, 4, 1, 2, 3, 1, 2, 3 };
    25         int[] A3 = { 1, 1, 2, 4, 2, 4, 3, 5, 3, 1, 2, 3, 4 };
    26         int[] A4 = { 1, 1 };
    27         int[] A5 = { 1, 1, 1, 2, 2, 2, 3, 3 };
    28         System.out.println(singleNumber(A1));
    29         System.out.println(singleNumber(A2));
    30         System.out.println(singleNumber(A3));
    31         System.out.println(singleNumber(A4));
    32         System.out.println(singleNumber(A5));
    33     }
    34 
    35     /**
    36      * 
    37      * @param A
    38      * @return
    39      */
    40     public static int singleNumber(int[] A) {
    41         Arrays.sort(A);
    42         int ret = 0;
    43         for (int i = 0; i < A.length; i = i + 3) {
    44             if (i == A.length - 1 || i == A.length - 2) {
    45                 ret = A[i];
    46                 break;
    47             } else if (!(A[i] == A[i + 1] && A[i] == A[i + 2])) {
    48                 ret = A[i];
    49                 break;
    50             }
    51         }
    52         return ret;
    53     }
    54 
    55 }
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  • 原文地址:https://www.cnblogs.com/Jellylovecode/p/Single-Number-2.html
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