1 ''' 2 有两个列表，分别存放来老男孩报名学习linux和python课程的学生名字 3 linux=['钢弹','小壁虎','小虎比','alex','wupeiqi','yuanhao'] 4 python=['dragon','钢弹','zhejiangF4','小虎比'] 5 ''' 6 # # 问题一：得出既报名linux又报名python的学生列表 7 8 ## 常规方法 9 # linux=['钢弹','小壁虎','小虎比','alex','wupeiqi','yuanhao'] 10 # python=['dragon','钢弹','zhejiangF4','小虎比'] 11 # l=[] 12 # for i in linux: 13 # for j in python: 14 # if i==j: 15 # l.append(i) 16 17 ## 列表解析处理 18 # linux=['钢弹','小壁虎','小虎比','alex','wupeiqi','yuanhao'] 19 # python=['dragon','钢弹','zhejiangF4','小虎比'] 20 # 21 # l = [i for i in linux for j in python if i == j] 22 # print(l) 23 24 # # 问题二：得出只报名linux，而没有报名python的学生列表 25 26 # linux=['钢弹','小壁虎','小虎比','alex','wupeiqi','yuanhao'] 27 # python=['dragon','钢弹','zhejiangF4','小虎比'] 28 # l=[i for i in linux if i not in python] 29 # print(l) 30 31 # 问题三：得出只报名python，而没有报名linux的学生列表 32 33 ''' 34 shares={ 35 'IBM':36.6, 36 'lenovo':27.3, 37 'huawei':40.3, 38 'oldboy':3.2, 39 'ocean':20.1 40 } 41 ''' 42 # # 问题一：得出股票价格大于30的股票名字列表 43 # shares={ 44 # 'IBM':36.6, 45 # 'lenovo':27.3, 46 # 'huawei':40.3, 47 # 'oldboy':3.2, 48 # 'ocean':20.1 49 # } 50 # s = [v for v in shares.values() if v > 30 ] 51 # print(s) 52 # # 问题二：求出所有股票的总价格 53 # 54 # l = [v for v in shares.values()] 55 # print(sum(l)) 56 57 ''' 58 l=[10,2,3,4,5,6,7] 59 得到一个新列表l1，新列表中每个元素是l中对应每个元素值的平方 60 过滤出l1中大于40的值，然后求和 61 ''' 62 # l=[10,2,3,4,5,6,7] 63 # l1 = [ i**2 for i in l ] 64 # 65 # l2 = [i for i in l1 if i > 40] 66 # print(sum(l2))