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  • B. Filya and Homework

    time limit per test
    1 second
    memory limit per test
    256 megabytes
    input
    standard input
    output
    standard output
     

    Today, hedgehog Filya went to school for the very first time! Teacher gave him a homework which Filya was unable to complete without your help.

    Filya is given an array of non-negative integers a1, a2, ..., an. First, he pick an integer x and then he adds x to some elements of the array (no more than once), subtract x from some other elements (also, no more than once) and do no change other elements. He wants all elements of the array to be equal.

    Now he wonders if it's possible to pick such integer x and change some elements of the array using this x in order to make all elements equal.

    Input

    The first line of the input contains an integer n (1 ≤ n ≤ 100 000) — the number of integers in the Filya's array. The second line containsn integers a1, a2, ..., an (0 ≤ ai ≤ 109) — elements of the array.

    Output

    If it's impossible to make all elements of the array equal using the process given in the problem statement, then print "NO" (without quotes) in the only line of the output. Otherwise print "YES" (without quotes).

    Examples
    input
    5
    1 3 3 2 1
    output
    YES
    input
    5
    1 2 3 4 5
    output
    NO
    Note

    In the first sample Filya should select x = 1, then add it to the first and the last elements of the array and subtract from the second and the third elements.

    运用了去重的unique函数 详见:http://www.cnblogs.com/Kiven5197/p/5873365.html

    附AC代码:

     1 #include<bits/stdc++.h>
     2 using namespace std;
     3 
     4 int a[100010];
     5 
     6 int main(){
     7     int n;
     8     while(cin>>n){
     9     for(int i=0;i<n;i++){
    10         cin>>a[i];
    11     }
    12     sort(a,a+n);
    13     int flag=0;
    14     int cnt=unique(a,a+n)-a;
    15     if(cnt<=2)
    16     flag=1;
    17     else if(cnt==3&&a[0]+a[2]==a[1]+a[1])
    18     flag=1;
    19     if(flag)
    20     cout<<"YES"<<endl;
    21     else
    22     cout<<"NO"<<endl;}
    23     return 0;
    24 }
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  • 原文地址:https://www.cnblogs.com/Kiven5197/p/5873361.html
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