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  • Uva10972(RevolC FaeLoN)

    题目链接:传送门

    题目大意:给你一副无向图,问至少加多少条边使图成为边双联通图

    题目思路:tarjan算法+缩点(如果已经是双连通图就直接输出0)

    #include <iostream>
    #include <cstdio>
    #include <cstdlib>
    #include <cmath>
    #include <algorithm>
    #include <cstring>
    #include <stack>
    #include <cctype>
    #include <queue>
    #include <string>
    #include <vector>
    #include <set>
    #include <map>
    #include <climits>
    #define lson root<<1,l,mid
    #define rson root<<1|1,mid+1,r
    #define fi first
    #define se second
    #define ping(x,y) ((x-y)*(x-y))
    #define mst(x,y) memset(x,y,sizeof(x))
    #define mcp(x,y) memcpy(x,y,sizeof(y))
    #define Min(x,y) (x<y?x:y)
    #define Max(x,y) (x>y?x:y)
    using namespace std;
    #define gamma 0.5772156649015328606065120
    #define MOD 1000000007
    #define inf 0x3f3f3f3f
    #define N 11005
    #define maxn 5005
    typedef long long LL;
    typedef pair<int,int> PII;
    
    stack<int>sk;
    int n,m,hcnt,deep,block,leaf;
    int d[maxn],dfn[maxn],low[maxn],head[maxn];
    int color[maxn],vis[maxn];
    struct Node{
        int to,next;
        Node(){}
        Node(int a,int b):to(a),next(b){}
    }node[N<<1];
    
    inline void add(int x,int y){
        node[hcnt]=Node(y,head[x]);
        head[x]=hcnt++;
    }
    
    inline void init(){
        while(!sk.empty())sk.pop();
        mst(vis,0);
        mst(head,-1);
        mst(d,0);
        mst(dfn,0);
        hcnt=deep=0;
        block=leaf=0;
    }
    
    void dfs(int x,int fa){
        int flag=1;  ///这个不是必要的,有重边时有效
        sk.push(x);
        vis[x]=1;
        low[x]=dfn[x]=++deep;
        for(int i=head[x];~i;i=node[i].next){
            int e=node[i].to;
            if(e==fa&&flag){flag=0;continue;}
            if(vis[e])low[x]=min(low[x],dfn[e]);
            else if(!dfn[e]){
                dfs(e,x);
                low[x]=min(low[x],low[e]);
            }
        }
        if(low[x]==dfn[x]){
            ++block;    ///缩点
            int co;
            do{
                co=sk.top();sk.pop();
                vis[co]=0;
                color[co]=block;
            }while(co!=x);
        }
    }
    
    int main(){
        int i,j,group,Case=0,x,y;
        while(scanf("%d%d",&n,&m)!=EOF){
            init();
            for(i=0;i<m;++i){
                scanf("%d%d",&x,&y);
                add(x,y);
                add(y,x);
            }
            for(i=1;i<=n;++i){
                if(!dfn[i])dfs(i,-1);
            }
            if(block==1){printf("0
    ");continue;}
            for(i=1;i<=n;++i)
            for(j=head[i];~j;j=node[j].next){
                int e=node[j].to;
                if(color[i]!=color[e])
                    ++d[color[i]];   ///d数组保留的是缩点后每个点的度数
            }
            for(i=1;i<=block;++i){
                if(d[i]==0)leaf+=2;  ///如果有孤立的点,叶子节点加2
                else if(d[i]==1)++leaf;
            }
            printf("%d
    ",(leaf+1)/2);
        }
        return 0;
    }
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  • 原文地址:https://www.cnblogs.com/Kurokey/p/5528477.html
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