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  • JZ-C-30

    剑指offer第三十题:最小的k个数

      1 //============================================================================
      2 // Name        : JZ-C-30.cpp
      3 // Author      : Laughing_Lz
      4 // Version     :
      5 // Copyright   : All Right Reserved
      6 // Description : 最小的k个数
      7 //============================================================================
      8 
      9 #include <iostream>
     10 #include <stdio.h>
     11 #include <set>
     12 #include <vector>
     13 #include "Array.h"
     14 using namespace std;
     15 
     16 using namespace std;
     17 
     18 // ====================方法1:同样可利用分治法====================
     19 void GetLeastNumbers_Solution1(int* input, int n, int* output, int k)
     20 {
     21     if(input == NULL || output == NULL || k > n || n <= 0 || k <= 0)
     22         return;
     23 
     24     int start = 0;
     25     int end = n - 1;
     26     int index = Partition(input, n, start, end);
     27     while(index != k - 1)
     28     {
     29         if(index > k - 1)
     30         {
     31             end = index - 1;
     32             index = Partition(input, n, start, end);
     33         }
     34         else
     35         {
     36             start = index + 1;
     37             index = Partition(input, n, start, end);
     38         }
     39     }
     40 
     41     for(int i = 0; i < k; ++i)
     42         output[i] = input[i];//查找后,放入output数组
     43 }
     44 
     45 // ====================方法2:堆、红黑树:set、multiset都是基于红黑树实现的====================
     46 typedef multiset<int, greater<int> >            intSet;
     47 typedef multiset<int, greater<int> >::iterator  setIterator;
     48 
     49 void GetLeastNumbers_Solution2(const vector<int>& data, intSet& leastNumbers, int k)
     50 {
     51     leastNumbers.clear();
     52 
     53     if(k < 1 || data.size() < k)
     54         return;
     55 
     56     vector<int>::const_iterator iter = data.begin();
     57     for(; iter != data.end(); ++ iter)
     58     {
     59         if((leastNumbers.size()) < k)
     60             leastNumbers.insert(*iter);
     61 
     62         else
     63         {
     64             setIterator iterGreatest = leastNumbers.begin();
     65 
     66             if(*iter < *(leastNumbers.begin()))
     67             {
     68                 leastNumbers.erase(iterGreatest);
     69                 leastNumbers.insert(*iter);
     70             }
     71         }
     72     }
     73 }
     74 
     75 // ====================测试代码====================
     76 void Test(char* testName, int* data, int n, int* expectedResult, int k)
     77 {
     78     if(testName != NULL)
     79         printf("%s begins: 
    ", testName);
     80 
     81     vector<int> vectorData;
     82     for(int i = 0; i < n; ++ i)
     83         vectorData.push_back(data[i]);
     84 
     85     if(expectedResult == NULL)
     86         printf("The input is invalid, we don't expect any result.
    ");
     87     else
     88     {
     89         printf("Expected result: 
    ");
     90         for(int i = 0; i < k; ++ i)
     91             printf("%d	", expectedResult[i]);
     92         printf("
    ");
     93     }
     94 
     95     printf("Result for solution1:
    ");
     96     int* output = new int[k];
     97     GetLeastNumbers_Solution1(data, n, output, k);
     98     if(expectedResult != NULL)
     99     {
    100         for(int i = 0; i < k; ++ i)
    101             printf("%d	", output[i]);
    102         printf("
    ");
    103     }
    104 
    105     delete[] output;
    106 
    107     printf("Result for solution2:
    ");
    108     intSet leastNumbers;
    109     GetLeastNumbers_Solution2(vectorData, leastNumbers, k);
    110     printf("The actual output numbers are:
    ");
    111     for(setIterator iter = leastNumbers.begin(); iter != leastNumbers.end(); ++iter)
    112         printf("%d	", *iter);
    113     printf("
    
    ");
    114 }
    115 
    116 // k小于数组的长度
    117 void Test1()
    118 {
    119     int data[] = {4, 5, 1, 6, 2, 7, 3, 8};
    120     int expected[] = {1, 2, 3, 4};
    121     Test("Test1", data, sizeof(data) / sizeof(int), expected, sizeof(expected) / sizeof(int));
    122 }
    123 
    124 // k等于数组的长度
    125 void Test2()
    126 {
    127     int data[] = {4, 5, 1, 6, 2, 7, 3, 8};
    128     int expected[] = {1, 2, 3, 4, 5, 6, 7, 8};
    129     Test("Test2", data, sizeof(data) / sizeof(int), expected, sizeof(expected) / sizeof(int));
    130 }
    131 
    132 // k大于数组的长度
    133 void Test3()
    134 {
    135     int data[] = {4, 5, 1, 6, 2, 7, 3, 8};
    136     int* expected = NULL;
    137     Test("Test3", data, sizeof(data) / sizeof(int), expected, 10);
    138 }
    139 
    140 // k等于1
    141 void Test4()
    142 {
    143     int data[] = {4, 5, 1, 6, 2, 7, 3, 8};
    144     int expected[] = {1};
    145     Test("Test4", data, sizeof(data) / sizeof(int), expected, sizeof(expected) / sizeof(int));
    146 }
    147 
    148 // k等于0
    149 void Test5()
    150 {
    151     int data[] = {4, 5, 1, 6, 2, 7, 3, 8};
    152     int* expected = NULL;
    153     Test("Test5", data, sizeof(data) / sizeof(int), expected, 0);
    154 }
    155 
    156 // 数组中有相同的数字
    157 void Test6()
    158 {
    159     int data[] = {4, 5, 1, 6, 2, 7, 2, 8};
    160     int expected[] = {1, 2};
    161     Test("Test6", data, sizeof(data) / sizeof(int), expected, sizeof(expected) / sizeof(int));
    162 }
    163 
    164 // 输入空指针
    165 void Test7()
    166 {
    167     int* expected = NULL;
    168     Test("Test7", NULL, NULL, expected, 0);
    169 }
    170 
    171 int main(int argc, char** argv)
    172 {
    173     Test1();
    174     Test2();
    175     Test3();
    176     Test4();
    177     Test5();
    178     Test6();
    179     Test7();
    180 
    181     return 0;
    182 }

    关于Partition方法:

     1 // 《剑指Offer——名企面试官精讲典型编程题》代码
     2 // 著作权所有者:何海涛
     3 
     4 #include <stdlib.h>
     5 #include <stdio.h>
     6 #include "Array.h"
     7 #include <exception>
     8 
     9 // Random Partition
    10 int RandomInRange(int min, int max) {
    11     int random = rand() % (max - min + 1) + min;
    12     return random;
    13 }
    14 
    15 void Swap(int* num1, int* num2) {
    16     int temp = *num1;
    17     *num1 = *num2;
    18     *num2 = temp;
    19 }
    20 
    21 int Partition(int data[], int length, int start, int end) {
    22     if (data == NULL || length <= 0 || start < 0 || end >= length) {
    23         printf("Invalid Parameters");
    24         throw new std::exception();//这里括号里为什么不能加msg???!!!
    25     }
    26     int index = RandomInRange(start, end);
    27     Swap(&data[index], &data[end]);
    28 
    29     int small = start - 1;
    30     for (index = start; index < end; ++index) {
    31         if (data[index] < data[end]) {
    32             ++small;
    33             if (small != index)
    34                 Swap(&data[index], &data[small]);
    35         }
    36     }
    37 
    38     ++small;
    39     Swap(&data[small], &data[end]);
    40 
    41     return small;
    42 }
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  • 原文地址:https://www.cnblogs.com/Laughing-Lz/p/5594161.html
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