开发时需要把如“今天 12:15” "昨天 21:21" "前天 03: 02"之类的String转换成Date，所以写了个方法，有更好的写法的话欢迎留言
1 //获取今天、昨天、前天的某个时间的方法， 如"昨天 21:21" "前天 15:15" 2 private static Date getFormatDate(String updated) throws Exception{ 3 if (updated.substring(0, 2).equals("今天")){ 4 String partOfDate = updated.substring(3); 5 Calendar calendar = Calendar.getInstance(); 6 calendar.setTime(new Date()); 7 calendar.set(Calendar.HOUR_OF_DAY, 0); 8 calendar.set(Calendar.MINUTE, 0); 9 calendar.set(Calendar.SECOND, 0); 10 SimpleDateFormat todaySdf = new SimpleDateFormat("yyyy-MM-dd"); 11 String today = todaySdf.format(calendar.getTime()); 12 String finalString = today + " " + partOfDate; 13 SimpleDateFormat finalSdf = new SimpleDateFormat("yyyy-MM-dd HH:mm"); 14 return finalSdf.parse(finalString); 15 }else if (updated.substring(0,2).equals("昨天")){ 16 String partOfDate = updated.substring(3); 17 Calendar calendar = Calendar.getInstance(); 18 calendar.setTime(new Date()); 19 calendar.add(Calendar.DATE, -1); 20 calendar.set(Calendar.HOUR_OF_DAY, 0); 21 calendar.set(Calendar.MINUTE, 0); 22 calendar.set(Calendar.SECOND, 0); 23 SimpleDateFormat yesterdaySdf = new SimpleDateFormat("yyyy-MM-dd"); 24 String yesterday = yesterdaySdf.format(calendar.getTime()); 25 String finalString = yesterday + " " + partOfDate; 26 SimpleDateFormat finalSdf = new SimpleDateFormat("yyyy-MM-dd HH:mm"); 27 return finalSdf.parse(finalString); 28 }else if (updated.substring(0, 2).equals("前天")){ 29 String partOfDate = updated.substring(3); 30 Calendar calendar = Calendar.getInstance(); 31 calendar.setTime(new Date()); 32 calendar.add(Calendar.DATE, -2); 33 calendar.set(Calendar.HOUR_OF_DAY, 0); 34 calendar.set(Calendar.MINUTE, 0); 35 calendar.set(Calendar.SECOND, 0); 36 SimpleDateFormat daysBeforeSdf = new SimpleDateFormat("yyyy-MM-dd"); 37 String daysBefore = daysBeforeSdf.format(calendar.getTime()); 38 String finalString = daysBefore + " " + partOfDate; 39 SimpleDateFormat finalSdf = new SimpleDateFormat("yyyy-MM-dd HH:mm"); 40 return finalSdf.parse(finalString); 41 }else { 42 SimpleDateFormat sdf = new SimpleDateFormat("yyyy-MM-dd HH:mm"); 43 return sdf.parse(updated); 44 } 45 }
Written on Dec. 14th, 2019