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  • Java8 新特性_Lambda 表达式

     

    1. Java8新特性_简介

    • Lambda 表达式
    • 函数式接口
    • 方法引用与构造器引用
    • Stream API
    • 接口中的默认方法与静态方法
    • 新时间日期 API
    • 减少空指针异常的容器 Optional

    2. Java8新特性_为什么使用 Lambda 表达式

    减少实现功能的代码行数,增加源码的可读性。

    导入项目代码后,发现有感叹号提示丢失jdk依赖的解决。

    导入项目代码后,发现有源码中文注释乱码的解决。

    Employee是一个实体类,具有id、name、age、salary成员属性,需求是实现根据一些限定条件对容器进行检索并打印输出。

    public class Employee
    package com.atguigu.java8;
    
    public class Employee {
    
        private int id;
        private String name;
        private int age;
        private double salary;
    
        public Employee() {
        }
    
        public Employee(String name) {
            this.name = name;
        }
    
        public Employee(String name, int age) {
            this.name = name;
            this.age = age;
        }
    
        public Employee(int id, String name, int age, double salary) {
            this.id = id;
            this.name = name;
            this.age = age;
            this.salary = salary;
        }
    
        public int getId() {
            return id;
        }
    
        public void setId(int id) {
            this.id = id;
        }
    
        public String getName() {
            return name;
        }
    
        public void setName(String name) {
            this.name = name;
        }
    
        public int getAge() {
            return age;
        }
    
        public void setAge(int age) {
            this.age = age;
        }
    
        public double getSalary() {
            return salary;
        }
    
        public void setSalary(double salary) {
            this.salary = salary;
        }
    
        public String show() {
            return "测试方法引用!";
        }
    
        @Override
        public int hashCode() {
            final int prime = 31;
            int result = 1;
            result = prime * result + age;
            result = prime * result + id;
            result = prime * result + ((name == null) ? 0 : name.hashCode());
            long temp;
            temp = Double.doubleToLongBits(salary);
            result = prime * result + (int) (temp ^ (temp >>> 32));
            return result;
        }
    
        @Override
        public boolean equals(Object obj) {
            if (this == obj)
                return true;
            if (obj == null)
                return false;
            if (getClass() != obj.getClass())
                return false;
            Employee other = (Employee) obj;
            if (age != other.age)
                return false;
            if (id != other.id)
                return false;
            if (name == null) {
                if (other.name != null)
                    return false;
            } else if (!name.equals(other.name))
                return false;
            if (Double.doubleToLongBits(salary) != Double.doubleToLongBits(other.salary))
                return false;
            return true;
        }
    
        @Override
        public String toString() {
            return "Employee [id=" + id + ", name=" + name + ", age=" + age + ", salary=" + salary + "]";
        }
    
    }
    View Code

    public class TestLambda1

    使用 Arrays.asList(…数组元素…)方法返回一个List接口的对象

    //需求:获取公司中年龄小于 35 的员工信息

    public List<Employee> filterEmployeeAge(List<Employee> emps){

    public void test3(){

        List<Employee> emps = Arrays.asList(
                new Employee(101, "张三", 18, 9999.99),
                new Employee(102, "李四", 59, 6666.66),
                new Employee(103, "王五", 28, 3333.33),
                new Employee(104, "赵六", 8, 7777.77),
                new Employee(105, "田七", 38, 5555.55)
        );
    
        //需求:获取公司中年龄小于 35 的员工信息
        public List<Employee> filterEmployeeAge(List<Employee> emps){
            List<Employee> list = new ArrayList<>();
            
            for (Employee emp : emps) {
                if(emp.getAge() <= 35){
                    list.add(emp);
                }
            }
            
            return list;
        }
        
        @Test
        public void test3(){
            List<Employee> list = filterEmployeeAge(emps);
            //增强for循环遍历集合
            for (Employee employee : list) {
                System.out.println(employee);
            }
        }
    View Code

    //需求:获取公司中工资大于 5000 的员工信息

    可以先对需求1调用方法得到结果list,然后在把结果list作为参数传到实现需求2的方法里。

    新的需求产生后,又得重复大量的代码,这谁顶得住啊。组合数。

        //需求:获取公司中工资大于 5000 的员工信息
        public List<Employee> filterEmployeeSalary(List<Employee> emps){
            List<Employee> list = new ArrayList<>();
            
            for (Employee emp : emps) {
                if(emp.getSalary() >= 5000){
                    list.add(emp);
                }
            }
            
            return list;
        }
    View Code

    //优化方式一:策略设计模式

    创建一个函数式接口 public interface MyPredicate<T> {

    package com.atguigu.java8;
    
    //抽象方法有且仅有一个
    @FunctionalInterface
    public interface MyPredicate<T> {
        
        boolean test(T t);
        
    }
    View Code

    public class FilterEmployeeForAge implements MyPredicate<Employee>{

    package com.atguigu.java8;
    
    public class FilterEmployeeForAge implements MyPredicate<Employee>{
    
        @Override
        public boolean test(Employee t) {
            return t.getAge() <= 35;
        }
    
    }
    View Code

    public class FilterEmployeeForSalary implements MyPredicate<Employee> {

    package com.atguigu.java8;
    
    public class FilterEmployeeForSalary implements MyPredicate<Employee> {
    
        @Override
        public boolean test(Employee t) {
            return t.getSalary() >= 5000;
        }
    
    }
    View Code

    编写一个抽取冗余代码的方法 public List<Employee> filterEmployee(List<Employee> emps, MyPredicate<Employee> mp){

    用接口实例化对象的方法,替换硬编码在if(###)小括号里的判断条件。

        //优化方式一:策略设计模式
        public List<Employee> filterEmployee(List<Employee> emps, MyPredicate<Employee> mp){
            List<Employee> list = new ArrayList<>();
            
            for (Employee employee : emps) {
                if(mp.test(employee)){
                    list.add(employee);
                }
            }
            
            return list;
        }
        
        @Test
        public void test4(){
            List<Employee> list = filterEmployee(emps, new FilterEmployeeForAge());
            for (Employee employee : list) {
                System.out.println(employee);
            }
            
            System.out.println("------------------------------------------");
            
            List<Employee> list2 = filterEmployee(emps, new FilterEmployeeForSalary());
            for (Employee employee : list2) {
                System.out.println(employee);
            }
        }
    View Code

    //优化方式二:匿名内部类 

    //需求:获取公司中id小于等于 103 的员工信息

    不用创建类.java文件,更进一步优化编码。

        //优化方式二:匿名内部类
        @Test
        public void test5(){
            List<Employee> list = filterEmployee(emps, new MyPredicate<Employee>() {
                @Override
                public boolean test(Employee t) {
                    //需求:获取公司中id小于等于 103 的员工信息
                    return t.getId() <= 103;
                }
            });
            
            for (Employee employee : list) {
                System.out.println(employee);
            }
        }
    View Code

    //优化方式三:Lambda 表达式 

        //优化方式三:Lambda 表达式
        @Test
        public void test6(){
            List<Employee> list = filterEmployee(emps, (e) -> e.getAge() <= 35);
            list.forEach(System.out::println);
            
            System.out.println("------------------------------------------");
            
            List<Employee> list2 = filterEmployee(emps, (e) -> e.getSalary() >= 5000);
            list2.forEach(System.out::println);
        }
    View Code

    //优化方式四:Stream API

        //优化方式四:Stream API
        @Test
        public void test7(){
            emps.stream()
                .filter((e) -> e.getAge() <= 35)
                .forEach(System.out::println);
            
            System.out.println("----------------------------------------------");
            
            emps.stream()
                .map(Employee::getName)
                .limit(3)
                .sorted()
                .forEach(System.out::println);
        }
    View Code

    3. Java8新特性_Lambda 基础语法 

     一、Lambda 表达式的基础语法:Java8中引入了一个新的操作符 "->"

    Lambda 表达式的参数列表的数据类型可以省略不写,因为JVM编译器通过上下文推断出数据类型,即“类型推断”

     语法格式一:无参数,无返回值
     () -> System.out.println("Hello Lambda!");

        @Test
        public void test1(){
            int num = 0;//jdk 1.7 前,必须是 final的,现在可以省略
            
            Runnable r = new Runnable() {
                @Override
                public void run() {
                    System.out.println("Hello World!" + num);
                }
            };        
            r.run();
            
            System.out.println("-------------------------------");
            
            Runnable r1 = () -> System.out.println("Hello Lambda!");
            r1.run();
        }
    View Code

     语法格式二:有一个参数,并且无返回值

     (x) -> System.out.println(x);

     语法格式三:若只有一个参数,小括号可以省略不写
     x -> System.out.println(x);

        @Test
        public void test2(){
            Consumer<String> con = x -> System.out.println(x);
            con.accept("我们程序员很威武!");
        }
    View Code

     语法格式四:有两个以上的参数,有返回值,并且 Lambda 体中有多条语句

     ->右侧需要有大括号方法体

        @Test
        public void test3(){
            Comparator<Integer> com = (x, y) -> {
                System.out.println("函数式接口");
                return Integer.compare(x, y);
            };
        }
    View Code

     语法格式五:若 Lambda 体中只有一条语句, return 和 大括号都可以省略不写
     Comparator<Integer> com = (x, y) -> Integer.compare(x, y);

        @Test
        public void test4(){
            Comparator<Integer> com = (x, y) -> Integer.compare(x, y);
        }
    View Code

     二、Lambda 表达式需要“函数式接口”的支持

     函数式接口:接口中只有一个抽象方法的接口,称为函数式接口。 可以使用注解 @FunctionalInterface 修饰
     可以检查是否是函数式接口

    //需求:对一个数进行运算

    先创建一个函数式接口

    package com.atguigu.java8;
    
    @FunctionalInterface
    public interface MyFun {
    
        Integer getValue(Integer num);
        
    }
    View Code

    再用Lambda表达式实现接口

        //需求:对一个数进行运算
        @Test
        public void test6(){
            Integer num = operation(100, (x) -> x * x);
            System.out.println(num);
            
            System.out.println(operation(200, (y) -> y + 200));
        }
        
        public Integer operation(Integer num, MyFun mf){
            return mf.getValue(num);
        }
    View Code

    4. Java8新特性_Lambda 练习

    public class Employee {

    package com.atguigu.java8;
    
    public class Employee {
    
        private int id;
        private String name;
        private int age;
        private double salary;
    
        public Employee() {
        }
    
        public Employee(String name) {
            this.name = name;
        }
    
        public Employee(String name, int age) {
            this.name = name;
            this.age = age;
        }
    
        public Employee(int id, String name, int age, double salary) {
            this.id = id;
            this.name = name;
            this.age = age;
            this.salary = salary;
        }
    
        public int getId() {
            return id;
        }
    
        public void setId(int id) {
            this.id = id;
        }
    
        public String getName() {
            return name;
        }
    
        public void setName(String name) {
            this.name = name;
        }
    
        public int getAge() {
            return age;
        }
    
        public void setAge(int age) {
            this.age = age;
        }
    
        public double getSalary() {
            return salary;
        }
    
        public void setSalary(double salary) {
            this.salary = salary;
        }
    
        public String show() {
            return "测试方法引用!";
        }
    
        @Override
        public int hashCode() {
            final int prime = 31;
            int result = 1;
            result = prime * result + age;
            result = prime * result + id;
            result = prime * result + ((name == null) ? 0 : name.hashCode());
            long temp;
            temp = Double.doubleToLongBits(salary);
            result = prime * result + (int) (temp ^ (temp >>> 32));
            return result;
        }
    
        @Override
        public boolean equals(Object obj) {
            if (this == obj)
                return true;
            if (obj == null)
                return false;
            if (getClass() != obj.getClass())
                return false;
            Employee other = (Employee) obj;
            if (age != other.age)
                return false;
            if (id != other.id)
                return false;
            if (name == null) {
                if (other.name != null)
                    return false;
            } else if (!name.equals(other.name))
                return false;
            if (Double.doubleToLongBits(salary) != Double.doubleToLongBits(other.salary))
                return false;
            return true;
        }
    
        @Override
        public String toString() {
            return "Employee [id=" + id + ", name=" + name + ", age=" + age + ", salary=" + salary + "]";
        }
    
    }
    View Code

    问题1解答

    List<Employee> emps = Arrays.asList(

    Collections.sort(emps,实现了接口的Lambda表达式);

        List<Employee> emps = Arrays.asList(
                new Employee(101, "张三", 18, 9999.99),
                new Employee(102, "李四", 59, 6666.66),
                new Employee(103, "王五", 28, 3333.33),
                new Employee(104, "赵六", 8, 7777.77),
                new Employee(105, "田七", 38, 5555.55)
        );
        
        @Test
        public void test1(){
            Collections.sort(emps, (e1, e2) -> {
                //成员变量age是基本数据类型
                if(e1.getAge() == e2.getAge()){
                        return e1.getName().compareTo(e2.getName());
                }else{
                   //return Integer.compare(e1.getAge(), e2.getAge());
                    return -Integer.compare(e1.getAge(), e2.getAge());
                }
            });
            
            for (Employee emp : emps) {
                System.out.println(emp);
            }
        }
    View Code

    问题2解答

    先创建一个函数式接口

    package com.atguigu.exer;
    
    @FunctionalInterface
    public interface MyFunction {
        
        public String getValue(String str);
    
    }
    View Code

    写一个方法输入上面的接口作第二个形参

        @Test
        public void test2(){
            String trimStr = strHandler("			 我们程序员很威武   ", (str) -> str.trim());
            System.out.println(trimStr);
            
            String upper = strHandler("abcdef", (str) -> str.toUpperCase());
            System.out.println(upper);
            
            String newStr = strHandler("我们程序员很威武", (str) -> str.substring(2, 5));
            System.out.println(newStr);
        }
        
        //需求:用于处理字符串
        public String strHandler(String str, MyFunction mf){
            return mf.getValue(str);
        }
    View Code

    问题3解答

    public interface MyFunction2<T, R> {

    package com.atguigu.exer;
    
    public interface MyFunction2<T, R> {
    
        public R getValue(T t1, T t2);
        
    }
    View Code

    public void op(Long l1, Long l2, MyFunction2<Long, Long> mf){

        @Test
        public void test3(){
            op(100L, 200L, (x, y) -> x + y);
            
            op(100L, 200L, (x, y) -> x * y);
        }
        
        //需求:对于两个 Long 型数据进行处理
        public void op(Long l1, Long l2, MyFunction2<Long, Long> mf){
            System.out.println(mf.getValue(l1, l2));
        }
    View Code

    5. Java8新特性_四大内置核心函数式接口 

    public class TestLambda3 {

    package com.atguigu.java8;
    
    import java.util.ArrayList;
    import java.util.Arrays;
    import java.util.List;
    import java.util.function.Consumer;
    import java.util.function.Function;
    import java.util.function.Predicate;
    import java.util.function.Supplier;
    
    import org.junit.Test;
    
    /*
     * Java8 内置的四大核心函数式接口
     * 
     * Consumer<T> : 消费型接口
     *         void accept(T t);
     * 
     * Supplier<T> : 供给型接口
     *         T get(); 
     * 
     * Function<T, R> : 函数型接口
     *         R apply(T t);
     * 
     * Predicate<T> : 断言型接口
     *         boolean test(T t);
     * 
     */
    public class TestLambda3 {
        
        //Predicate<T> 断言型接口:
        @Test
        public void test4(){
            List<String> list = Arrays.asList("Hello", "atguigu", "Lambda", "www", "ok");
            List<String> strList = filterStr(list, (s) -> s.length() > 3);
            
            for (String str : strList) {
                System.out.println(str);
            }
        }
        
        //需求:将满足条件的字符串,放入集合中
        public List<String> filterStr(List<String> list, Predicate<String> pre){
            List<String> strList = new ArrayList<>();
            
            for (String str : list) {
                if(pre.test(str)){
                    strList.add(str);
                }
            }
            
            return strList;
        }
        
        //Function<T, R> 函数型接口:
        @Test
        public void test3(){
            String newStr = strHandler("			 我大尚硅谷威武   ", (str) -> str.trim());
            System.out.println(newStr);
            
            String subStr = strHandler("我大尚硅谷威武", (str) -> str.substring(2, 5));
            System.out.println(subStr);
        }
        
        //需求:用于处理字符串
        public String strHandler(String str, Function<String, String> fun){
            return fun.apply(str);
        }
        
        //Supplier<T> 供给型接口 :
        @Test
        public void test2(){
            List<Integer> numList = getNumList(10, () -> (int)(Math.random() * 100));
            
            for (Integer num : numList) {
                System.out.println(num);
            }
        }
        
        //需求:产生指定个数的整数,并放入集合中
        public List<Integer> getNumList(int num, Supplier<Integer> sup){
            List<Integer> list = new ArrayList<>();
            
            for (int i = 0; i < num; i++) {
                Integer n = sup.get();
                list.add(n);
            }
            
            return list;
        }
        
        //Consumer<T> 消费型接口 :
        @Test
        public void test1(){
            happy(10000, (m) -> System.out.println("你们刚哥喜欢大宝剑,每次消费:" + m + "元"));
        } 
        
        public void happy(double money, Consumer<Double> con){
            con.accept(money);
        }
    }
    View Code

    6. Java8新特性_方法引用与构造器引用 

    * 一、方法引用:若 Lambda 体中的功能,已经有方法提供了实现,可以使用方法引用
    * (可以将方法引用理解为 Lambda 表达式的另外一种表现形式)
    *
    * 1. 对象的引用 :: 实例方法名
    *
    * 2. 类名 :: 静态方法名
    *
    * 3. 类名 :: 实例方法名

    package com.atguigu.java8;
    
    import java.io.PrintStream;
    import java.util.Comparator;
    import java.util.function.BiFunction;
    import java.util.function.BiPredicate;
    import java.util.function.Consumer;
    import java.util.function.Function;
    import java.util.function.Supplier;
    
    import org.junit.Test;
    
    /*
     * 一、方法引用:若 Lambda 体中的功能,已经有方法提供了实现,可以使用方法引用
     *                   (可以将方法引用理解为 Lambda 表达式的另外一种表现形式)
     * 
     * 1. 对象的引用 :: 实例方法名
     * 
     * 2. 类名 :: 静态方法名
     * 
     * 3. 类名 :: 实例方法名
     * 
     * 注意:
     *      ①方法引用所引用的方法的参数列表与返回值类型,需要与函数式接口中抽象方法的参数列表和返回值类型保持一致!
     *      ②若Lambda 的参数列表的第一个参数,是实例方法的调用者,第二个参数(或无参)是实例方法的参数时,格式: ClassName::MethodName
     * 
     * 二、构造器引用 :构造器的参数列表,需要与函数式接口中参数列表保持一致!
     * 
     * 1. 类名 :: new
     * 
     * 三、数组引用
     * 
     *     类型[] :: new;
     * 
     * 
     */
    public class TestMethodRef {
        //数组引用
        @Test
        public void test8(){
            Function<Integer, String[]> fun = (args) -> new String[args];
            String[] strs = fun.apply(10);
            System.out.println(strs.length);
            
            System.out.println("--------------------------");
            
            Function<Integer, Employee[]> fun2 = Employee[] :: new;
            Employee[] emps = fun2.apply(20);
            System.out.println(emps.length);
        }
        
        //构造器引用
        @Test
        public void test7(){
            Function<String, Employee> fun = Employee::new;
            
            BiFunction<String, Integer, Employee> fun2 = Employee::new;
        }
        
        @Test
        public void test6(){
            Supplier<Employee> sup = () -> new Employee();
            System.out.println(sup.get());
            
            System.out.println("------------------------------------");
            
            Supplier<Employee> sup2 = Employee::new;
            System.out.println(sup2.get());
        }
        
        //类名 :: 实例方法名
        @Test
        public void test5(){
            BiPredicate<String, String> bp = (x, y) -> x.equals(y);
            System.out.println(bp.test("abcde", "abcde"));
            
            System.out.println("-----------------------------------------");
            
            BiPredicate<String, String> bp2 = String::equals;
            System.out.println(bp2.test("abc", "abc"));
            
            System.out.println("-----------------------------------------");
            
            
            Function<Employee, String> fun = (e) -> e.show();
            System.out.println(fun.apply(new Employee()));
            
            System.out.println("-----------------------------------------");
            
            Function<Employee, String> fun2 = Employee::show;
            System.out.println(fun2.apply(new Employee()));
            
        }
        
        //类名 :: 静态方法名
        @Test
        public void test4(){
            Comparator<Integer> com = (x, y) -> Integer.compare(x, y);
            
            System.out.println("-------------------------------------");
            
            Comparator<Integer> com2 = Integer::compare;
        }
        
        @Test
        public void test3(){
            BiFunction<Double, Double, Double> fun = (x, y) -> Math.max(x, y);
            System.out.println(fun.apply(1.5, 22.2));
            
            System.out.println("--------------------------------------------------");
            
            BiFunction<Double, Double, Double> fun2 = Math::max;
            System.out.println(fun2.apply(1.2, 1.5));
        }
    
        //对象的引用 :: 实例方法名
        @Test
        public void test2(){
            Employee emp = new Employee(101, "张三", 18, 9999.99);
            
            Supplier<String> sup = () -> emp.getName();
            System.out.println(sup.get());
            
            System.out.println("----------------------------------");
            
            Supplier<String> sup2 = emp::getName;
            System.out.println(sup2.get());
        }
        
        @Test
        public void test1(){
            PrintStream ps = System.out;
            Consumer<String> con = (str) -> ps.println(str);
            con.accept("Hello World!");
            
            System.out.println("--------------------------------");
            
            Consumer<String> con2 = ps::println;
            con2.accept("Hello Java8!");
            
            Consumer<String> con3 = System.out::println;
        }
        
    }
    View Code
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  • 原文地址:https://www.cnblogs.com/MarlonKang/p/12357202.html
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