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  • 求日期所属星座的 TSQL UDF (用户自定义函数)

    use northwind
    go
    create function udf_GetStar (@ datetime)
    returns varchar(100)
    -- 返回日期所属星座,如果有静态的 星座对照码表 直接在查询中 join 效率相对更高
    begin
    return
    (
    --declare @ datetime
    --set @ = getdate()
    select max(star)
    from
    (
    select '魔羯座' as star,1 as [month],1 as [day]
    union all select '水瓶座',1,20
    union all select '双鱼座',2,19
    union all select '牡羊座',3,21
    union all select '金牛座',4,20
    union all select '双子座',5,21
    union all select '巨蟹座',6,22
    union all select '狮子座',7,23
    union all select '处女座',8,23
    union all select '天秤座',9,23
    union all select '天蝎座',10,24
    union all select '射手座',11,22
    union all select '魔羯座',12,22
    ) stars
    where [month] * 40 + [day]
    =
    (
    select max([month] * 40 + [day])
    from (
    select '魔羯座' as star,1 as [month],1 as [day]
    union all select '水瓶座',1,20
    union all select '双鱼座',2,19
    union all select '牡羊座',3,21
    union all select '金牛座',4,20
    union all select '双子座',5,21
    union all select '巨蟹座',6,22
    union all select '狮子座',7,23
    union all select '处女座',8,23
    union all select '天秤座',9,23
    union all select '天蝎座',10,24
    union all select '射手座',11,22
    union all select '魔羯座',12,22
    ) stars
    where [month] * 40 + [day] <= month(@) * 40 + day(@)
    )
    )
    end
    go
    CREATE FUNCTION GetStar1(@ datetime)
    RETURNS varchar(100)
    AS
    BEGIN
    --仅一句 SQL 搞定
    --如果有静态的 星座对照码表 直接在查询中 join 效率相对更高
    RETURN
    (
    --declare @ datetime
    --set @ = getdate()
    select max(star)
    from
    (
    -- 星座,该星座开始日期所属月,该星座开始日期所属日
    select '魔羯座' as star,1 as [month],1 as [day]
    union all select '水瓶座',1,20
    union all select '双鱼座',2,19
    union all select '牧羊座',3,21
    union all select '金牛座',4,20
    union all select '双子座',5,21
    union all select '巨蟹座',6,22
    union all select '狮子座',7,23
    union all select '处女座',8,23
    union all select '天秤座',9,23
    union all select '天蝎座',10,24
    union all select '射手座',11,22
    union all select '魔羯座',12,22
    ) stars
    where dateadd(day,[day]-1,dateadd(month,[month]-1,dateadd(year,datediff(year,0,@),0)))
    =
    (
    select max(dateadd(day,[day]-1,dateadd(month,[month]-1,dateadd(year,datediff(year,0,@),0))))
    from
    (
    select '魔羯座' as star,1 as [month],1 as [day]
    union all select '水瓶座',1,20
    union all select '双鱼座',2,19
    union all select '牧羊座',3,21
    union all select '金牛座',4,20
    union all select '双子座',5,21
    union all select '巨蟹座',6,22
    union all select '狮子座',7,23
    union all select '处女座',8,23
    union all select '天秤座',9,23
    union all select '天蝎座',10,24
    union all select '射手座',11,22
    union all select '魔羯座',12,22
    ) stars
    where @ >= dateadd(day,[day]-1,dateadd(month,[month]-1,dateadd(year,datediff(year,0,@),0)))
    )
    )
    end

    go

    declare @ datetime
    set @ = getdate()


    select *
    from stars
    where [month] * 40 + [day] =
    (
    select max(stars.[month] * 40 + stars.[day])
    from stars
    where stars.[month] * 40 + stars.[day] <= month(@) * 40 + day(@)
    )

    go
    select c.birthdate,a.star
    from employees c
    left join stars a
    on month(c.birthdate) * 40 + day(c.birthdate) >= a.month * 40 + a.day
    left join stars b
    on a.month * 40 + a.day < b.month * 40 + b.day
    and b.month * 40 + b.day  = (select min(month * 40 + day) from stars where month * 40 + day > a.month * 40 + a.day)
    where month(c.birthdate) * 40 + day(c.birthdate) < isnull(b.month * 40 + b.day,999)

    select *
    from stars a
    left join stars b
    on a.month * 40 + a.day < b.month * 40 + b.day
    and b.month * 40 + b.day  = (select min(month * 40 + day) from stars where month * 40 + day > a.month * 40 + a.day)

    select a.birthdate,b.star,dbo.udf_getstar1(a.birthdate),dbo.udf_getstar(a.birthdate)
    from employees a
    left join
    (
    select a.*,isnull(b.month,12) as m,isnull(b.day,31) as d
    from stars a
    left join stars b
    on a.month * 40 + a.day < b.month * 40 + b.day
    and b.month * 40 + b.day  = (select min(month * 40 + day) from stars where month * 40 + day > a.month * 40 + a.day)
    ) b
    on month(a.birthdate) * 40 + day(a.birthdate) >= b.month * 40 +  b.day
    and month(a.birthdate) * 40 + day(a.birthdate) < b.m * 40 +  b.d


    select e.birthdate,a.star
    from employees e
    left join stars a
    on month(e.birthdate) * 40 + day(e.birthdate) >= a.month * 40 + a.day
    left join stars b
    on a.month * 40 + a.day < b.month * 40 + b.day
    and b.month * 40 + b.day  = (select min(month * 40 + day) from stars where month * 40 + day > a.month * 40 + a.day)
    where month(e.birthdate) * 40 + day(e.birthdate) < isnull(b.month * 40 + b.day,999)
    go


    --测试
    use northwind
    select dbo.getstar(birthdate),count(*)
    from employees
    group by dbo.getstar(birthdate)

    create  function Weekday(@Date datetime)
    returns integer
    begin
    --1: Monday , ... ,7: Sunday
    return (select (@@datefirst + datepart(weekday,@Date)) % 7
            + case when (@@datefirst + datepart(weekday,@Date)) % 7 < 2
                        then 6
                   else -1
              end)
    end

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  • 原文地址:https://www.cnblogs.com/Microshaoft/p/2485749.html
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