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  • 在不破坏原加密存储过程的前提下,解密存储过程!(补充j9988)

    实为 转贴j9988+原创

    begin transaction? --playyuer 原创
    exec sp_decrypt 'AppSP_test' --j9988 原创
    rollback transaction --playyuer 原创

    or:或者直接用 transaction 把 j9988 包起来!
    begin transaction
    j9988
    rollback transaction

    /************* 解密存储过程 **********
    ------------------------sql2000大于40000的-----------------
    原作:j9988 号:J老师
    */
    alter? PROCEDURE sp_decrypt (@objectName varchar(50))
    AS
    begin

    begin transaction --add by playyuer

    declare @objectname1 varchar(100)
    declare @sql1 nvarchar(4000),@sql2 nvarchar(4000),@sql3 nvarchar(4000),@sql4 nvarchar(4000),@sql5 nvarchar(4000),@sql6 nvarchar(4000),@sql7 nvarchar(4000),@sql8 nvarchar(4000),@sql9 nvarchar(4000),@sql10 nvarchar(4000)?
    DECLARE? @OrigSpText1 nvarchar(4000),? @OrigSpText2 nvarchar(4000) , @OrigSpText3 nvarchar(4000), @resultsp nvarchar(4000)
    declare? @i int , @t bigint
    declare @m int,@n int,@q int
    set @m=(SELECT max(colid) FROM syscomments? WHERE id = object_id(@objectName))
    set @n=1
    --get encrypted data
    create table? #temp(colid int,ctext varbinary(8000))
    insert #temp SELECT colid,ctext FROM syscomments? WHERE id = object_id(@objectName)
    set @sql1='ALTER PROCEDURE '+ @objectName +' WITH ENCRYPTION AS '
    --set @sql1='ALTER PROCEDURE '+ @objectName +' WITH ENCRYPTION AS '
    set @q=len(@sql1)
    set @sql1=@sql1+REPLICATE('-',4000-@q)
    select @sql2=REPLICATE('-',4000),@sql3=REPLICATE('-',4000),@sql4=REPLICATE('-',4000),@sql5=REPLICATE('-',4000),@sql6=REPLICATE('-',4000),@sql7=REPLICATE('-',4000),@sql8=REPLICATE('-',4000),@sql9=REPLICATE('-',4000),@sql10=REPLICATE('-',4000)
    exec(@sql1+@sql2+@sql3+@sql4+@sql5+@sql6+@sql7+@sql8+@sql9+@sql10)
    while @n<=@m
    begin
    SET @OrigSpText1=(SELECT ctext FROM #temp? WHERE colid=@n)
    set @objectname1=@objectname+'_t'
    SET @OrigSpText3=(SELECT ctext FROM syscomments WHERE id=object_id(@objectName) and colid=@n)
    if @n=1
    begin
    SET @OrigSpText2='CREATE PROCEDURE '+ @objectName +' WITH ENCRYPTION AS '--
    set @q=4000-len(@OrigSpText2)
    set @OrigSpText2=@OrigSpText2+REPLICATE('-',@q)
    end
    else
    begin
    SET @OrigSpText2=REPLICATE('-', 4000)
    end
    --start counter
    SET @i=1
    --fill temporary variable
    SET @resultsp = replicate(N'A', (datalength(@OrigSpText1) / 2))

    --loop
    WHILE @i<=datalength(@OrigSpText1)/2
    BEGIN
    --reverse encryption (XOR original+bogus+bogus encrypted)
    SET @resultsp = stuff(@resultsp, @i, 1, NCHAR(UNICODE(substring(@OrigSpText1, @i, 1)) ^
    ??????????????????????????????? (UNICODE(substring(@OrigSpText2, @i, 1)) ^
    ??????????????????????????????? UNICODE(substring(@OrigSpText3, @i, 1)))))
    ??? SET @i=@i+1
    END
    --drop original SP
    --EXECUTE ('drop PROCEDURE '+ @objectName)
    --remove encryption
    --preserve case
    SET @resultsp=REPLACE((@resultsp),'WITH ENCRYPTION', '')
    SET @resultsp=REPLACE((@resultsp),'With Encryption', '')
    SET @resultsp=REPLACE((@resultsp),'with encryption', '')
    IF CHARINDEX('WITH ENCRYPTION',UPPER(@resultsp) )>0
    ? SET @resultsp=REPLACE(UPPER(@resultsp),'WITH ENCRYPTION', '')
    --replace Stored procedure without enryption
    print @resultsp
    --execute( @resultsp)
    set @n=@n+1
    end
    drop table #temp
    end
    rollback transaction --add by playyuer
    GO

    /*
    适合40000字符。
    每次4000 print出来,自已贴。
    切记:我见过的解过程都是对原过程进行破坏。破解前一定要备份!!!!
    超过40000的,自已加SQL(我上面用SQL.SQL2--SQL10)
    超长的可加SQL11--sql20........
    */


    ?

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  • 原文地址:https://www.cnblogs.com/Microshaoft/p/2485781.html
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