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  • 不同样式输出菱形

    不同样式输出菱形

    1、实心菱形

    package mrzhangxd.xyz.demo;
    
    /**
     * CopyRight (C),2019
     *
     * @Package: mrzhangxd.xyz.demo
     * @Name: Test
     * @Auther: zhangxiaodong3
     * @Creatte: 2019/12/19
     * @Description: Output 7 lines of solid diamonds
     */
    
    /*
    Output style:
        *
       ***
      *****
       ***
        *
    Main idea:
    
        1. Divide 7 rows of diamonds into 4 and 3 columns for output;
    
        2.The first half
            "*" Quantity per line: 2 * i-1
            Number of spaces per line: line-i
        3. The lower part:
            Number of spaces per line: i
            "*" Quantity per line: 2 * i-1
     */
    public class Test {
    
        public static void main(String[] args){
    
            // The number of input lines is L, and the output diamond is (2L-1)
            int L = 4;
    
            // The first half of the output (4 lines)
            for(int i = 1; i <= L; i++){
    
                // Output the space of each line in the top half
                for(int j = 1;j <= (L - i); j++){
    
                   System.out.print(" ");
    
                }
    
                // Output the "*" sign of each line in the lower half
                for(int j = 1; j <= (2*i)-1; j++){
    
                    System.out.print("*");
    
                }
    
                System.out.println();
            }
    
    
            // The lower part of the output (3 lines)
            for(int i = 1; i <= (L-1);i++){
    
                // Output spaces for each line in the lower half
                for(int j = 1;j <= i;j++){
    
                    System.out.print(" ");
                }
    
                // Output "*" sign for each line in the lower half
                for(int j = 1; j <= (2*(L-i)-1);j++){
    
                    System.out.print("*");
                }
    
                System.out.println();
            }
    
        }
    
    }
    

    2、空心菱形

    package mrzhangxd.xyz.demo;
    
    /**
     * CopyRight (C),2019
     *
     * @PackageName: mrzhangxd.xyz.demo
     * @ClassName: Test2
     * @Auther: zhangxiaodong3
     * @Created: 2019/12/1915:51
     * @Description: Output 7 rows of hollow diamonds...
     */
    /*
    Output style:
         *
        * *
       *   *
        * *
         *
    
    Main idea:
    
        1. Divide 7 rows of diamonds into 4 and 3 columns for output;
    
        2.The first half
            "*" Quantity per line: 2 * i-1
            Number of spaces per line: line-i
        3. The lower part:
            Number of spaces per line: i
            "*" Quantity per line: 2 * i-1
        4. Consider where to output spaces and where to output "*"
            Set the line number to "n", then the position of the output "*" is:
            (j == 1 | j == ((2 * n) -1))
    
     */
    public class Test2 {
    
        public static void main(String[] args){
    
            // The number of input lines is L, and the output diamond is (2L-1)
            int L = 4;
    
            // Determine the number of rows in the upper half of the output diamond
            for(int i = 1;i <= L; i ++){
    
                // Output the number of spaces per line
                for(int j = 1;j <= (L-i);j++){
    
                    System.out.print(" ");
                }
    
    
                // Output the number of "*" in each line
                for(int j = 1;j <= ((2*i)-1);j++){
    
    
                    // Output "*" in the if condition, otherwise output spaces
                    if(j == 1 || j == ((2*i)-1)){
    
                       System.out.print("*");
    
                    }else{
    
                        System.out.print(" ");
    
                    }
                }
    
                System.out.println();
    
            }
    
            // Determine the number of rows of the output diamond in the lower half
            for(int i = 1;i <= (L-1);i++){
    
    
                // Output the number of spaces per line
                for(int j = 1;j <= i;j++){
    
                    System.out.print(" ");
    
                }
    
                // Output the number of "*" in each line
                for(int j = 1;j <= (2*(L-i)-1);j++){
    
    
                    // Output "*" in the if condition, otherwise output spaces
                    if(j == 1 || j == 2*(L-i)-1){
    
                        System.out.print("*");
    
                    }else{
    
                        System.out.print(" ");
                    }
    
    
                }
    
                System.out.println();
            }
    
        }
    
    }
    

    PS:上代码就可以了,思路代码注解里有...

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  • 原文地址:https://www.cnblogs.com/MrZhangxd/p/12069177.html
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