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  • Leetcode刷题记录[java]——695 Max Area of Island

    一、前言

    二、题695 Max Area of Island

    Given a non-empty 2D array grid of 0's and 1's, an island is a group of 1's (representing land) connected 4-directionally (horizontal or vertical.) You may assume all four edges of the grid are surrounded by water.

    Find the maximum area of an island in the given 2D array. (If there is no island, the maximum area is 0.)

    Example 1:

      [[0,0,1,0,0,0,0,1,0,0,0,0,0],
       [0,0,0,0,0,0,0,1,1,1,0,0,0],
       [0,1,1,0,1,0,0,0,0,0,0,0,0],
       [0,1,0,0,1,1,0,0,1,0,1,0,0],
       [0,1,0,0,1,1,0,0,1,1,1,0,0],
       [0,0,0,0,0,0,0,0,0,0,1,0,0],
       [0,0,0,0,0,0,0,1,1,1,0,0,0],
       [0,0,0,0,0,0,0,1,1,0,0,0,0]]
    

    Given the above grid, return 6. Note the answer is not 11, because the island must be connected 4-directionally.

    Example 2:

      [[0,0,0,0,0,0,0,0]]

    Given the above grid, return 0.

    Note: The length of each dimension in the given grid does not exceed 50.

    三、解题思路

       遍历数组,求每个岛的面积,两两作比,返回最大值。

     1 class Solution {
     2     public int maxAreaOfIsland(int[][] grid) {
     3         int max_area = 0;
     4         for(int i = 0; i < grid.length; i++)
     5             for(int j = 0; j < grid[0].length; j++)
     6                 if(grid[i][j] == 1) max_area = Math.max(max_area, AreaOfIsland(grid, i, j));
     7         return max_area;
     8     }
     9     
    10     public int AreaOfIsland(int[][] grid, int i, int j){
    11         if(i>=0 && i < grid.length && j>=0 && j < grid[0].length && grid[i][j] == 1){
    12             grid[i][j] = 0;
    13             return 1 + AreaOfIsland(grid, i+1, j) + AreaOfIsland(grid, i-1, j) + AreaOfIsland(grid, i, j-1) + AreaOfIsland(grid, i, j+1);
    14         }
    15         return 0;
    16     }
    17 }
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    函数的参数 2018-3-27
  • 原文地址:https://www.cnblogs.com/Myoungs/p/7833300.html
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