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  • re | [MRCTF2020]Transform

    过节划个水,做一个1分题。

    这是一个windows x64的逆向。

    肥肠简单的异或。

    有点太简单了,不说明了,丢脚本:

     1 aim = [
     2 0x67,0x79,0x7B,0x7F,0x75,0x2B,0x3C,0x52,0x53,0x79,0x57,0x5E,0x5D,0x42,0x7B,0x2D,0x2A,0x66,0x42,0x7E,0x4C,0x57,0x79,0x41,0x6B,0x7E,0x65,0x3C,0x5C,0x45,0x6F,0x62,0x4D
     3 ]
     4 
     5 table = [
     6 0x09,0x0A,0x0F,0x17,0x07,0x18,0x0C,0x06,0x01,0x10,0x03,0x11,0x20,0x1D,0x0B,0x1E,0x1B,0x16,0x04,0x0D,0x13,0x14,0x15,0x02,0x19,0x05,0x1F,0x08,0x12,0x1A,0x1C,0x0E,0x00
     7 ]
     8 
     9 flag = []
    10 for i in range(33):
    11     for j in range(33,127):
    12         if j ^ table[i] == aim[i]:
    13             flag.append(chr(j))
    14             break
    15 
    16 print(''.join(flag))
    17 _flag = [0 for i in range(33)]
    18 for i in range(33):
    19     _flag[table[i]] = flag[i]
    20     
    21 print(''.join(_flag))
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  • 原文地址:https://www.cnblogs.com/Mz1-rc/p/13767992.html
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