两组牌中两张牌相比能赢的就连,后求最大匹配。
#include <cmath> #include <cstdlib> #include <cstdio> #include <cstring> #include <algorithm> #include <fstream> #include <iostream> #define rep(i, l, r) for(int i=l; i<=r; i++) #define clr(x, c) memset(x, c, sizeof(x)) #define N 32 #define MAX 1<<30 #define ll long long using namespace std; int read() { int x=0, f=1; char ch=getchar(); while (ch<'0' || ch>'9') { if (ch=='-') f=-1; ch=getchar(); } while (ch>='0' && ch<='9') { x=x*10+ch-'0'; ch=getchar(); } return x*f; } int read2() { char s[5]; scanf("%s", s); int a; if (s[0]=='T') a=32; else if (s[0]=='J') a=36; else if (s[0]=='Q') a=40; else if (s[0]=='K') a=44; else if (s[0]=='A') a=48; else a=(s[0]-'2')*4; if (s[1]=='H') a+=3; else if (s[1]=='S') a+=2; else if (s[1]=='D') a+=1; return a; } struct edge{int y, n;} e[N*N]; int fir[N], en; int n, ka[N], kb[N], k[N], ans; bool b[N]; void Add(int x, int y) { en++, e[en].y=y, e[en].n=fir[x], fir[x]=en; } bool Find(int x) { int o=fir[x], y=e[o].y; while (o) { if (!b[y]) { b[y]=1; if (!k[y] || Find(k[y])) { k[y]=x; return true; } } o=e[o].n, y=e[o].y; } return false; } int main() { int t=read(); while (t--) { clr(fir, 0); clr(k, 0); en=ans=0; n=read(); rep(i, 1, n) ka[i]=read2(); rep(i, 1, n) kb[i]=read2(); rep(i, 1, n) rep(j, 1, n) if (kb[j] > ka[i]) Add(i, j); rep(i, 1, n) { clr(b, 0); if (Find(i)) ans++; } printf("%d ", ans); } return 0; }