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  • Mysql 查询所有课程的成绩第2名到第3名的学生信息及该课程成绩

     查询所有课程的成绩第2名到第3名的学生信息及该课程成绩

    1. 查询课程ID为‘01’ 的课程的成绩第2名到第3名的学生信息及该课程成绩

    SELECT
      d.*, c.排名, c.s_score, c.c_id
    FROM
      ( SELECT
    a.s_id, a.s_score, a.c_id, @i:=@i+1 AS 排名 FROM score a,(SELECT @i:=0)s WHERE a.c_id='01' ORDER BY a.s_score DESC )c LEFT JOIN student d ON c.s_id = d.s_id WHERE 排名 BETWEEN 2 AND 3

    2. 查询课程ID为‘02’ 的课程的成绩第2名到第3名的学生信息及该课程成绩

    SELECT
      d.*, c.排名, c.s_score, c.c_id 
    FROM
      ( SELECT a.s_id, a.s_score, a.c_id, @j:=@j+1 AS 排名 FROM score a,(SELECT @j:=0)s WHERE a.c_id='02' ORDER BY a.s_score DESC )c
    LEFT JOIN 
        student d 
    ON
        c.s_id = d.s_id
    WHERE 
        排名 BETWEEN 2 AND 3

    3. 查询课程ID为‘03’ 的课程的成绩第2名到第3名的学生信息及该课程成绩

    SELECT
      d.*, c.排名, c.s_score, c.c_id 
    FROM
      ( SELECT a.s_id, a.s_score, a.c_id, @k:=@k+1 AS 排名 FROM score a,(SELECT @k:=0)s WHERE a.c_id='02' ORDER BY a.s_score DESC )c
    LEFT JOIN 
        student d 
    ON
        c.s_id = d.s_id
    WHERE 
        排名 BETWEEN 2 AND 3

    4. 联合

    SELECT
      d.*, c.排名, c.s_score, c.c_id 
    FROM
      ( SELECT a.s_id, a.s_score, a.c_id, @i:=@i+1 AS 排名 FROM score a,(SELECT @i:=0)s WHERE a.c_id='02' ORDER BY a.s_score DESC )c
    LEFT JOIN 
        student d 
    ON
        c.s_id = d.s_id
    WHERE 
        排名 BETWEEN 2 AND 3
    UNION
    SELECT
      d.*, c.排名, c.s_score, c.c_id 
    FROM
      ( SELECT a.s_id, a.s_score, a.c_id, @j:=@j+1 AS 排名 FROM score a,(SELECT @j:=0)s WHERE a.c_id='02' ORDER BY a.s_score DESC )c
    LEFT JOIN 
        student d 
    ON
        c.s_id = d.s_id
    WHERE 
        排名 BETWEEN 2 AND 3
    UNION
    SELECT
      d.*, c.排名, c.s_score, c.c_id 
    FROM
      ( SELECT a.s_id, a.s_score, a.c_id, @k:=@k+1 AS 排名 FROM score a,(SELECT @k:=0)s WHERE a.c_id='02' ORDER BY a.s_score DESC )c
    LEFT JOIN 
        student d 
    ON
        c.s_id = d.s_id
    WHERE 
        排名 BETWEEN 2 AND 3

    5. 查询结果

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  • 原文地址:https://www.cnblogs.com/PersonalDiary/p/12531591.html
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