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  • Java Convert String to Binary

    This article shows you five examples to convert a string into a binary string representative or vice verse.

    本文向您展示了五个示例,这些示例将字符串转换为二进制字符串表示形式,反之亦然。

    1. Convert String to Binary – Integer.toBinaryString
    2. Convert String to Binary – Bit Masking
    3. Convert Binary to String – Integer.parseInt
    4. Convert Unicode String to Binary.
    5. Convert Binary to Unicode String.

    1. Convert String to Binary – Integer.toBinaryString

    The steps to convert a string to its binary format.

    1. Convert string to char[].
    2. Loops the char[].
    3. Integer.toBinaryString(aChar) to convert chars to a binary string.
    4. String.format to create padding if need.
    package com.mkyong.convert;
    
    import java.util.ArrayList;
    import java.util.List;
    import java.util.stream.Collectors;
    
    public class StringToBinaryExample01 {
    
        public static void main(String[] args) {
    
            String input = "Hello";
            String result = convertStringToBinary(input);
    
            System.out.println(result);
    
            // pretty print the binary format
            System.out.println(prettyBinary(result, 8, " "));
        }
    
        public static String convertStringToBinary(String input) {
    
            StringBuilder result = new StringBuilder();
            char[] chars = input.toCharArray();
    
            for (char aChar : chars) {
                result.append(String.format("%8s", Integer.toBinaryString(aChar)).replaceAll(" ", "0"));	// char -> int, auto-cast zero pads
            }
            return result.toString();
        }
    
        public static String prettyBinary(String binary, int blockSize, String separator) {
    
            List<String> result = new ArrayList<>();
            int index = 0;
            while (index < binary.length()) {
                result.add(binary.substring(index, Math.min(index + blockSize, binary.length())));	
                index += blockSize;
            }
            return result.stream().collect(Collectors.joining(separator));
        }
    }
    
    Output
    0100100001100101011011000110110001101111
    01001000 01100101 01101100 01101100 01101111
    

    2. Convert String to Binary – Bit Masking.

    2.1 This Java example will use bit masking technique to generate binary format from an 8-bit byte.

    package com.mkyong.convert;
    
    import java.nio.charset.StandardCharsets;
    import java.util.ArrayList;
    import java.util.List;
    import java.util.stream.Collectors;
    
    public class StringToBinaryExample02 {
    
        public static void main(String[] args) {
    
            String input = "a";
            String result = convertByteArraysToBinary(input.getBytes(StandardCharsets.UTF_8));
            System.out.println(prettyBinary(result, 8, " "));
        }
    
        public static String convertByteArraysToBinary(byte[] input) {
    
            StringBuilder result = new StringBuilder();
            for (byte b : input) {
                int val = b;
                for (int i = 0; i < 8; i++) {
                    result.append((val & 128) == 0 ? 0 : 1);    // 128 = 1000 00000
                    val <<= 1;
                }
            }
            return result.toString();
        }
    
        public static String prettyBinary(String binary, int blockSize, String separator) {
    
            List<String> result = new ArrayList<>();
            int index = 0;
            while (index < binary.length()) {
                result.add(binary.substring(index, Math.min(index + blockSize, binary.length())));
                index += blockSize;
            }
            
            return result.stream().collect(Collectors.joining(separator));
        }
    }
    

    Output

    01100001
    

    The hard part is this code. The idea is similar to this Java – Convert Integer to Binary using bit masking. In Java, byte is an 8-bit, int is 32-bit, for integer 128 the binary is 1000 0000.

    困难的部分是这段代码。这个想法类似于–使用位掩码将整数转换为二进制。在Java中,字节是8位,整数是32位,对于整数128,二进制是1000 0000。

    for (byte b : input) {
        int val = b;                                      // byte -> int
        for (int i = 0; i < 8; i++) {
            result.append((val & 128) == 0 ? 0 : 1);      // 128 = 1000 0000
            val <<= 1;                                    // val = val << 1
        }
    }
    

    This & is an Bitwise AND operator, only 1 & 1 is 1, other combinations are all 0.

    1 & 1 = 1
    1 & 0 = 0
    0 & 1 = 0
    0 & 0 = 0
    

    This val <<= 1 is actually val = val << 1, it is a bit left shift operator, it moves the bits to the left side by 1 bit.

    Review the following draft: let’s assume the val is an int, or byte represents a character a.

    00000000 | 00000000 | 00000000 | 01100001   # val  = a in binary
    00000000 | 00000000 | 00000000 | 10000000   # 128
    &                                           # bitwise AND
    00000000 | 00000000 | 00000000 | 00000000   # (val & 128) == 0 ? 0 : 1, result = 0
    
    00000000 | 00000000 | 00000000 | 11000010   # val << 1
    00000000 | 00000000 | 00000000 | 10000000   # 128
    &                                           # bitwise AND
    00000000 | 00000000 | 00000000 | 10000000   # (val & 128) == 0 ? 0 : 1, result = 1
    
    00000000 | 00000000 | 00000001 | 10000100   # val << 1
    00000000 | 00000000 | 00000000 | 10000000   # 128
    &
    00000000 | 00000000 | 00000000 | 10000000   # result = 1
    
    00000000 | 00000000 | 00000011 | 00001000   # val << 1
    00000000 | 00000000 | 00000000 | 10000000   # 128
    &
    00000000 | 00000000 | 00000000 | 00000000   # result = 0
    
    00000000 | 00000000 | 00000110 | 00010000   # val << 1
    00000000 | 00000000 | 00000000 | 10000000   # 128
    &
    00000000 | 00000000 | 00000000 | 00000000   # result = 0
    
    00000000 | 00000000 | 00001100 | 00100000   # val << 1
    00000000 | 00000000 | 00000000 | 10000000   # 128
    &
    00000000 | 00000000 | 00000000 | 00000000   # result = 0
    
    00000000 | 00000000 | 00011000 | 01000000   # val << 1
    00000000 | 00000000 | 00000000 | 10000000   # 128
    &
    00000000 | 00000000 | 00000000 | 00000000   # result = 0
    
    00000000 | 00000000 | 00110000 | 10000000   # val << 1
    00000000 | 00000000 | 00000000 | 10000000   # 128
    &
    00000000 | 00000000 | 00000000 | 10000000   # result = 1
    
    # collect all bits                          # 01100001
    

    For string a the binary string is 01100001.

    3. Convert Binary to String.

    In Java, we can use Integer.parseInt(str, 2) to convert a binary string to a string.

    package com.mkyong.crypto.bytes;
    
    import java.util.Arrays;
    import java.util.stream.Collectors;
    
    public class StringToBinaryExample03 {
    
        public static void main(String[] args) {
    
            String input = "01001000 01100101 01101100 01101100 01101111";
    
            // Java 11 makes life easier
            String raw = Arrays.stream(input.split(" "))
                    .map(binary -> Integer.parseInt(binary, 2))
                    .map(Character::toString)
                    .collect(Collectors.joining()); // cut the space
    
            System.out.println(raw);
        }
    }
    

    4. Convert Unicode String to Binary.

    We can use Unicode to represent non-English characters since Java String supports Unicode, we can use the same bit masking technique to convert a Unicode string to a binary string.

    由于Java String支持Unicode,因此可以使用Unicode来表示非英语字符,我们还可以使用相同的位掩码技术将Unicode字符串转换为二进制字符串。

    This example converts a single Chinese character (It means you in English) to a binary string.

    package com.mkyong.crypto.bytes;
    
    import java.nio.charset.StandardCharsets;
    import java.util.ArrayList;
    import java.util.List;
    import java.util.stream.Collectors;
    
    public class UnicodeToBinary01 {
    
        public static void main(String[] args) {
    
            byte[] input = "你".getBytes(StandardCharsets.UTF_8);
            System.out.println(input.length);	// 3, 1 Chinese character = 3 bytes
            String binary = convertByteArraysToBinary(input);
            System.out.println(binary);
            System.out.println(prettyBinary(binary, 8, " "));
        }
    
        public static String convertByteArraysToBinary(byte[] input) {
    
            StringBuffer result = new StringBuffer();
            for (byte b : input) {
                int val = b;
                for (int i = 0; i < 8; i++) {
                    result.append((val & 128) == 0 ? 0 : 1);    // 128 = 1000 0000
                    val <<= 1;
                }
            }
            return result.toString();
        }
    
        public static String prettyBinary(String binary, int blockSize, String separator) {
            
            List<String> result = new ArrayList<>();
            int index = 0;
            while (index < binary.length()) {
                result.add(binary.substring(index, Math.min(index + blockSize, binary.length())));
                index += blockSize;
            }
            return result.stream().collect(Collectors.joining(separator));
        }
    }
    

    Output

    3
    111001001011110110100000
    11100100 10111101 10100000
    

    Different Unicode requires different bytes, and not all Chinese characters required 3 bytes of storage, some may need more or fewer bytes.

    不同的Unicode需要不同的字节,并非所有汉字都需要3个字节的存储空间,有些可能需要更多或更少的字节。

    5. Convert Binary to Unicode String.

    Read comments for self-explanatory.

    package com.mkyong.crypto.bytes;
    
    import java.nio.ByteBuffer;
    import java.nio.charset.StandardCharsets;
    
    public class UnicodeToBinary02 {
    
        public static void main(String[] args) {
    
            String binary = "111001001011110110100000";     // 你, Chinese character
            String result = binaryUnicodeToString(binary);
            System.out.println(result.trim());
        }
    
        // <= 32bits = 4 bytes, int needs 4 bytes
        public static String binaryUnicodeToString(String binary) {
    
            byte[] array = ByteBuffer.allocate(4)
                    .putInt(Integer.parseInt(binary, 2))    // 4 bytes byte[]
                    .array();
    
            return new String(array, StandardCharsets.UTF_8);
        }
    }
    

    Output

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  • 原文地址:https://www.cnblogs.com/PrimerPlus/p/13185621.html
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