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  • 203. Remove Linked List Elements

    Remove all elements from a linked list of integers that have value val.

    Example
    Given: 1 --> 2 --> 6 --> 3 --> 4 --> 5 --> 6, val = 6
    Return: 1 --> 2 --> 3 --> 4 --> 5

    本题比较简单,构造一个dummy头即可。

    移位删除时,存在与不存在的删除办法不同

    /**
     * Definition for singly-linked list.
     * public class ListNode {
     *     int val;
     *     ListNode next;
     *     ListNode(int x) { val = x; }
     * }
     */
    public class Solution {
        public ListNode removeElements(ListNode head, int val) {
            if (head == null) return head;
            ListNode dummy = new ListNode(0);
            dummy.next = head;
            ListNode prev = dummy;
            ListNode curr = dummy.next;
            while(curr.next != null) {
                if(curr.val == val) {
                    prev.next = curr.next;
                    curr = curr.next;
                }
                else {
                    prev = prev.next;
                    curr = curr.next;
                }
            }
            if(curr.next == null) {
                if(curr.val == val) prev.next = null;
            }
            return dummy.next;
            
        }
    }
    

      

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  • 原文地址:https://www.cnblogs.com/Raymond-Yang/p/5216296.html
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