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  • Codeforces 424C(异或)

    Time Limit: 2000MS   Memory Limit: 262144KB   64bit IO Format: %I64d & %I64u

     Status

    Description

    People in the Tomskaya region like magic formulas very much. You can see some of them below.

    Imagine you are given a sequence of positive integer numbers p1p2, ..., pn. Lets write down some magic formulas:

    Here, "mod" means the operation of taking the residue after dividing.

    The expression  means applying the bitwise xor (excluding "OR") operation to integers x and y. The given operation exists in all modern programming languages. For example, in languages C++ and Java it is represented by "^", in Pascal — by "xor".

    People in the Tomskaya region like magic formulas very much, but they don't like to calculate them! Therefore you are given the sequence p, calculate the value of Q.

    Input

    The first line of the input contains the only integer n (1 ≤ n ≤ 106). The next line contains n integers: p1, p2, ..., pn (0 ≤ pi ≤ 2·109).

    Output

    The only line of output should contain a single integer — the value of Q.

    Sample Input

    Input
    3
    1 2 3
    Output
    3

    Source

    Codeforces Round #242 (Div. 2)
    #include<stdio.h>
    #include<string.h>
    #include<iostream>
    using namespace std;
    typedef long long LL;
    int a[1000005],b[1000005];
    int main()
    {
        int i,j,t,len,n,s,ans;
        while(scanf("%d",&n)!=EOF)
        {
            scanf("%d",&t);
            ans=t;
            for(i=2;i<=n;i++)
            {
                scanf("%d",&t);
                ans^=t;
            }
            b[0]=0;
            for(i=1;i<=n;i++)
            {
                b[i]=b[i-1]^i;
                int tmp=n/i;
                if(tmp&1)
                ans^=b[i-1];
                if(n%i)
                ans=ans^b[n%i];
            }
            printf("%d
    ",ans);
        }
        return 0;
    }
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  • 原文地址:https://www.cnblogs.com/Ritchie/p/5425248.html
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