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  • Codeforces Round #321 (Div. 2) A. Kefa and First Steps【暴力/dp/最长不递减子序列】

    A. Kefa and First Steps
    time limit per test
    2 seconds
    memory limit per test
    256 megabytes
    input
    standard input
    output
    standard output

    Kefa decided to make some money doing business on the Internet for exactly n days. He knows that on the i-th day (1 ≤ i ≤ n) he makes ai money. Kefa loves progress, that's why he wants to know the length of the maximum non-decreasing subsegment in sequence ai. Let us remind you that the subsegment of the sequence is its continuous fragment. A subsegment of numbers is called non-decreasing if all numbers in it follow in the non-decreasing order.

    Help Kefa cope with this task!

    Input

    The first line contains integer n (1 ≤ n ≤ 105).

    The second line contains n integers a1,  a2,  ...,  an (1 ≤ ai ≤ 109).

    Output

    Print a single integer — the length of the maximum non-decreasing subsegment of sequence a.

    Examples
    input
    6
    2 2 1 3 4 1
    output
    3
    input
    3
    2 2 9
    output
    3
    Note

    In the first test the maximum non-decreasing subsegment is the numbers from the third to the fifth one.

    In the second test the maximum non-decreasing subsegment is the numbers from the first to the third one.

    【代码】:

    #include <bits/stdc++.h>
    
    using namespace std;
    const int N = 1e5+100;
    int n,a[N],ans,maxn;
    int main()
    {
        cin>>n;
        for(int i=0;i<n;i++)//0开始
             cin>>a[i];
        for(int i=1;i<=n;i++)//1开始
        {
            if(a[i]>=a[i-1])
            {
                ans++;
                maxn=max(maxn,ans);
            }
            else
                ans=0;
        }
        cout<<maxn+1<<endl;
        return 0;
    }
    View Code
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  • 原文地址:https://www.cnblogs.com/Roni-i/p/7928443.html
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