Given an array S of n integers, find three integers in S such that the sum is closest to a given number, target. Return the sum of the three integers. You may assume that each input would have exactly one solution.
For example, given array S = {-1 2 1 -4}, and target = 1.
The sum that is closest to the target is 2. (-1 + 2 + 1 = 2).
思考:类似3Sum。
class Solution {
public:
int threeSumClosest(vector<int> &num, int target) {
// IMPORTANT: Please reset any member data you declared, as
// the same Solution instance will be reused for each test case.
int ret=INT_MAX;
sort(num.begin(),num.end());
int i,j,k,sum;
int min=INT_MAX;
for(i=0;i!=num.size();i++)
{
j=i+1;
k=num.size()-1;
while(j<k)
{
sum=num[i]+num[j]+num[k];
if(abs(target-sum)<min)
{
ret=sum;
min=abs(target-sum);
}
if(sum==target) return target;
else if(sum<target) j++;
else k--;
}
}
return ret;
}
};