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  • [LeetCode]3Sum Closest

    Given an array S of n integers, find three integers in S such that the sum is closest to a given number, target. Return the sum of the three integers. You may assume that each input would have exactly one solution.

        For example, given array S = {-1 2 1 -4}, and target = 1.
    
        The sum that is closest to the target is 2. (-1 + 2 + 1 = 2).
    

    思考:类似3Sum。

    class Solution {
    public:
        int threeSumClosest(vector<int> &num, int target) {
            // IMPORTANT: Please reset any member data you declared, as
            // the same Solution instance will be reused for each test case.
            int ret=INT_MAX;
    		sort(num.begin(),num.end());
    		int i,j,k,sum;
    		int min=INT_MAX;
    		for(i=0;i!=num.size();i++)
    		{
    			j=i+1;
    			k=num.size()-1;
    			while(j<k)
    			{
    				sum=num[i]+num[j]+num[k];
    				if(abs(target-sum)<min)
    				{
    					ret=sum;
    					min=abs(target-sum);
    				}
    				if(sum==target) return target;
    				else if(sum<target) j++;
    				else k--;
    			}
    		}
    		return ret;
        }
    };
    

      

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  • 原文地址:https://www.cnblogs.com/Rosanna/p/3415964.html
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