Problem Description
Lweb has a string S.
Oneday, he decided to transform this string to a new sequence.
You need help him determine this transformation to get a sequence which has the longest LIS(Strictly Increasing).
You need transform every letter in this string to a new number.
A is the set of letters of S, B is the set of natural numbers.
Every injection f:A→B can be treat as an legal transformation.
For example, a String “aabc”, A={a,b,c}, and you can transform it to “1 1 2 3”, and the LIS of the new sequence is 3.
Now help Lweb, find the longest LIS which you can obtain from S.
LIS: Longest Increasing Subsequence. (https://en.wikipedia.org/wiki/Longest_increasing_subsequence)
Oneday, he decided to transform this string to a new sequence.
You need help him determine this transformation to get a sequence which has the longest LIS(Strictly Increasing).
You need transform every letter in this string to a new number.
A is the set of letters of S, B is the set of natural numbers.
Every injection f:A→B can be treat as an legal transformation.
For example, a String “aabc”, A={a,b,c}, and you can transform it to “1 1 2 3”, and the LIS of the new sequence is 3.
Now help Lweb, find the longest LIS which you can obtain from S.
LIS: Longest Increasing Subsequence. (https://en.wikipedia.org/wiki/Longest_increasing_subsequence)
Input
The first line of the input contains the only integer T,(1≤T≤20).
Then T lines follow, the i-th line contains a string S only containing the lowercase letters, the length of S will not exceed 105.
Then T lines follow, the i-th line contains a string S only containing the lowercase letters, the length of S will not exceed 105.
Output
For each test case, output a single line "Case #x: y", where x is the case number, starting from 1. And y is the answer.
Sample Input
2
aabcc
acdeaa
Sample Output
Case #1: 3
Case #2: 4
题目大意:
有一个字符串,现在可以给不同的字母随便映射一个值。使得让映射值组成的串可能的LIS最大
大致思路:
一开始没看到随便映射,直接套一个LIS的模板,发现复杂度不可能。所以又重新读了一遍题。
既然是随便映射,并且不同字母映射的值肯定是不一样的。那么让求可能的最大值,其实就是数有多少个不同的字母。
把字母个数输出就好了。
代码:
1 #include<bits/stdc++.h> 2 using namespace std; 3 set<char> st; 4 int main() 5 { 6 ios::sync_with_stdio(false); 7 int t,cnt=1,ans; 8 string str; 9 cin>>t; 10 for(;cnt<=t;++cnt){ 11 st.clear(); 12 ans=0; 13 cin>>str; 14 for(int i=0;i<str.size();++i) 15 st.insert(str[i]); 16 ans=st.size(); 17 cout<<"Case #"<<cnt<<": "<<ans<<endl;; 18 } 19 return 0; 20 }