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  • 第六次作业

    1.编写一个简单程序,要求数组长度为5,静态赋值10,20,30,40,50,在控制台输出该数组的值。

    package test1;

    public class zhang {

        public static void main(String[] args) {
            // TODO Auto-generated method stub
            int[] arr={10,20,30,40,50};
            for(int i=0;i<5;i++){
                 System.out.println(arr[i]);      
                }           
            }
        }

    2.编写一个简单程序,要求数组长度为5,动态赋值10,20,30,40,50,在控制台输出该数组的值。

    package test1;
    public class zhang {
        public static void main(String[] args) {
            // TODO Auto-generated method stub
            int [] a = new int[5];
            a[0] = 10;
            a[1] = 20;
            a[2] = 30;
            a[3] = 40;
            a[4] = 50;
            for(int i = 0; i < a.length; i++) {
                System.out.println(a[i]);
            }
        }
    }

    3.编写一个简单程序,定义整型数组,里面的元素是{23,45,22,33,56},求数组元素的和、平均值

    package test1;
    public class zhang {
        public static void main(String[] args) {
            // TODO Auto-generated method stub
            int [] a = {23,45,22,33,56};
             double sum = 0;
             for(int i = 0; i < a.length; i++) {
              sum = sum + a[i];
             }
             System.out.println("数组元素的和是:" + sum);
             System.out.println("数组元素的平均值是:" + sum / a.length);
        }

    4.在一个有8个整数(18,25,7,36,13,2,89,63)的数组中找出其中最大的数及其下标

    package test1;
    public class zhang {
        public static void main(String[] args) {
            // TODO Auto-generated method stub
            int [] arr = {18,25,7,36,13,2,89,63};
            int max = arr[0];
            int a=0;
            for(int i = 1; i < arr.length; i++) {
                if(arr[i] > max){
                    max = arr[i];
                    a=i;
                }
            }
            System.out.println("数组中最大值是:"+ max);
            System.out.println("下标为:" + a);
        }
    }

     5.  将一个数组中的元素逆序存放(知识点:数组遍历、数组元素访问)

    package test1;

    public class zhang {
        public static void main(String[] args) {
            // TODO Auto-generated method stub
            int [] a = {23,56,7,94,15,2,35,73};
             for (int i = 0; i < a.length / 2; i++) { 
                  int t = a[i];
                  a[i] = a[a.length - 1 - i];
                  a[a.length - 1 - i] =t;
               } 
                  for (int i = 0; i < a.length; i++) { 
                    System.out.print(a[i] + " "); 
               }
            }
    }

     

    6.有一个已经排好序的数组。现输入一个数,要求按原来的规律将它插入数组中。

     package test1; public class finish {
        public static void main(String[] args) {
            // TODO Auto-generated method stub
            int[] m = {14,23,56,81};
            int[] n = new int[5];
            int a = 32;
            for(int i =0; i< m.length; i++){
                if(m[i] > a){
                    n[i] = a;
                    for(i = i + 1; i < n.length; i++ ){
                        n[i] = m[i-1];   
                    }
                }
                else{
                    n[i] = m[i];
                }
            }
            
            for(int i = 0; i<5; i++){
                System.out.println(n[i]);
            }
        }
    }

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  • 原文地址:https://www.cnblogs.com/SmileMRzhang/p/12666284.html
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