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  • MySQL最终任务

    MySQL任务就要完成了

     任务一

     sql代码

    SELECT 
    D.Name Department,
    E1.Name Name,
    Salary
    FROM employee E1
    INNER JOIN department D
    ON E1.DepartmentId = D.ID
    WHERE 
    (SELECT COUNT(*)
     FROM employee E2 
    WHERE E1.Salary <= E2.Salary AND E1.DepartmentId = E2.DepartmentId)
     <= 3

    运行结果:

     任务二

    sql语句:

    SELECT Score,(
    SELECT COUNT(*) FROM score
    WHERE Score > S.Score)+1 'Rank'
    FROM Score S
    ORDER BY Score DESC

     查询结果

     

    任务3

    项目十:行程和用户(难度:困难)
    Trips 表中存所有出租车的行程信息。每段行程有唯一键 Id,Client_Id 和 Driver_Id 是 Users 表中 Users_Id 的外键。Status 是枚举类型,枚举成员为 (‘completed’, ‘cancelled_by_driver’, ‘cancelled_by_client’)。
    +----+-----------+-----------+---------+--------------------+----------+
    | Id | Client_Id | Driver_Id | City_Id |        Status      |Request_at|
    +----+-----------+-----------+---------+--------------------+----------+
    | 1  |     1     |    10     |    1    |     completed      |2013-10-01|
    | 2  |     2     |    11     |    1    | cancelled_by_driver|2013-10-01|
    | 3  |     3     |    12     |    6    |     completed      |2013-10-01|
    | 4  |     4     |    13     |    6    | cancelled_by_client|2013-10-01|
    | 5  |     1     |    10     |    1    |     completed      |2013-10-02|
    | 6  |     2     |    11     |    6    |     completed      |2013-10-02|
    | 7  |     3     |    12     |    6    |     completed      |2013-10-02|
    | 8  |     2     |    12     |    12   |     completed      |2013-10-03|
    | 9  |     3     |    10     |    12   |     completed      |2013-10-03| 
    | 10 |     4     |    13     |    12   | cancelled_by_driver|2013-10-03|
    +----+-----------+-----------+---------+--------------------+----------+
    Users 表存所有用户。每个用户有唯一键 Users_Id。Banned 表示这个用户是否被禁止,Role 则是一个表示(‘client’, ‘driver’, ‘partner’)的枚举类型。
    +----------+--------+--------+
    | Users_Id | Banned |  Role  |
    +----------+--------+--------+
    |    1     |   No   | client |
    |    2     |   Yes  | client |
    |    3     |   No   | client |
    |    4     |   No   | client |
    |    10    |   No   | driver |
    |    11    |   No   | driver |
    |    12    |   No   | driver |
    |    13    |   No   | driver |
    +----------+--------+--------+
    写一段 SQL 语句查出 2013年10月1日 至 2013年10月3日 期间非禁止用户的取消率。基于上表,你的 SQL 语句应返回如下结果,取消率(Cancellation Rate)保留两位小数。
    +------------+-------------------+
    |     Day    | Cancellation Rate |
    +------------+-------------------+
    | 2013-10-01 |       0.33        |
    | 2013-10-02 |       0.00        |
    | 2013-10-03 |       0.50        |
    +------------+-------------------+
    SELECT Request_at Date_Day,
    ROUND(
    (
    SUM(IF(Status ='completed',0,1))
    /COUNT(*)
    ),2)
     Candle_Rate
    FROM Trips
    WHERE Client_Id IN 
    (SELECT Users_Id FROM Users WHERE Banned='No')
    OR
     Driver_Id IN 
    (SELECT Users_Id FROM Users WHERE Banned='No')
    GROUP BY Request_at

     查询结果:

     

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  • 原文地址:https://www.cnblogs.com/Thegonedays/p/10472829.html
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