Description
定义一个Point类和Circle类，用于判断给定的一系列的点是否在给定的圆内。
其中，Point类：
1.有2个成员x和y，分别为其横坐标和纵坐标；1个静态成员numOfPoints，用于计算生成的点的个数。
2.具有构造函数、析构函数和拷贝构造函数，具体格式输出根据样例自行判断。
3. 具有静态方法int getNumOfPoints()，用于返回numOfPoints的值。
4. 具有int getX()和int getY()方法，用于获取横坐标和纵坐标。
Circle类：
1. 拥有Point类的对象center，表示圆心坐标。拥有radius对象，表示圆的半径；1个静态成员numOfCircles，用于指示生成了多少个圆对象。
2. 具有构造函数、析构函数和拷贝构造函数，具体格式根据样例自行判断。
3.具有静态方法int getNumOfCircles()，返回numOfCircles的值。
4. 具有getCenter()方法，返回圆心坐标。注意：根据输出结果判断返回值类型。
5. 具有bool pointInCircle(Point &)方法，用于判断给定的点是否在当前圆内。是则返回true，否则返回false。
Input
输入分多行。
第一行M>0，表示有M个测试用例。
每个测试用例又包括多行。第1行包含3个整数，分别为一个圆的横坐标、纵坐标和半径。第2行N>0，表示之后又N个点，每个点占一行，分别为其横坐标和纵坐标。
所有输入均为整数，且在int类型范围内。
Output
输出见样例。注意：在圆的边上的点，不在圆内。
Sample Input
2
0 0 10
3
2 2
11 11
10 0
1 1 20
3
2 2
1 1
100 100
Sample Output
The Point (0, 0) is created!Now, we have 1 points.
The Point (1, 1) is created! Now, we have 2 points.
A circle at (1, 1) and radius 1 is created! Now, we have 1 circles.
We have 2 points and 1 circles now.
The Point (0, 0) is created! Now, we have 3 points.
A Point (0, 0) is copied! Now, we have 4 points.
A Point (0, 0) is copied! Now, we have 5 points.
A circle at (0, 0) and radius 10 is created! Now, we have 2 circles.
A Point (0, 0) is erased! Now, we have 4 points.
The Point (2, 2) is created! Now, we have 5 points.
(2, 2) is in the circle at (0, 0).
The Point (11, 11) is created! Now, we have 6 points.
(11, 11) is not in the circle at (0, 0).
The Point (10, 0) is created! Now, we have 7 points.
(10, 0) is not in the circle at (0, 0).
A Point (0, 0) is erased! Now, we have 6 points.
A circle at (0, 0) and radius 10 is erased! Now, we have 1 circles.
A Point (0, 0) is erased! Now, we have 5 points.
The Point (1, 1) is created! Now, we have 6 points.
A Point (1, 1) is copied! Now, we have 7 points.
A Point (1, 1) is copied! Now, we have 8 points.
A circle at (1, 1) and radius 20 is created! Now, we have 2 circles.
A Point (1, 1) is erased! Now, we have 7 points.
The Point (2, 2) is created! Now, we have 8 points.
(2, 2) is in the circle at (1, 1).
The Point (1, 1) is created! Now, we have 9 points.
(1, 1) is in the circle at (1, 1).
The Point (100, 100) is created! Now, we have 10 points.
(100, 100) is not in the circle at (1, 1).
A Point (1, 1) is erased! Now, we have 9 points.
A circle at (1, 1) and radius 20 is erased! Now, we have 1 circles.
A Point (1, 1) is erased! Now, we have 8 points.
We have 8 points, and 1 circles.
A circle at (1, 1) and radius 1 is erased!Now, we have 0 circles.
A Point (1, 1) is erased! Now, we have 7 points.
A Point (0, 0) is erased! Now, we have 6 points.
HINT
Append Code
#include<iostream>using namespace std;class Point{private: int x,y; static int numOfPoints;public: Point(int a,int b):x(a),y(b){numOfPoints++;cout<<"The Point ("<<x<<", "<<y<<") is created! Now, we have "<<numOfPoints<<" points.
";} ~Point(){numOfPoints--;cout<<"A Point ("<<x<<", "<<y<<") is erased! Now, we have "<<numOfPoints<<" points.
";} Point(const Point &q):x(q.x),y(q.y){numOfPoints++;cout<<"A Point ("<<x<<", "<<y<<") is copied! Now, we have "<<numOfPoints<<" points.
";} static int getNumOfPoints(){return numOfPoints;} int getX(){return x;} int getY(){return y;}};int Point::numOfPoints=0;class Circle{private: Point center; int radius; static int numOfCircles;public: Circle(Point b,int a):center(b),radius(a){numOfCircles++;cout<<"A circle at ("<<center.getX()<<", "<<center.getY()<<") and radius "<<radius<<" is created! Now, we have "<<numOfCircles<<" circles.
";} Circle(int a,int b,int c):center(a,b),radius(c){numOfCircles++;cout<<"A circle at ("<<center.getX()<<", "<<center.getY()<<") and radius "<<radius<<" is created! Now, we have "<<numOfCircles<<" circles.
";} ~Circle(){numOfCircles--;cout<<"A circle at ("<<center.getX()<<", "<<center.getY()<<") and radius "<<radius<<" is erased! Now, we have "<<numOfCircles<<" circles.
";} static int getNumOfCircles(){return numOfCircles;} Point &getCenter(){return center;} bool pointInCircle(Point &q) { int b=(q.getX()-center.getX())*(q.getX()-center.getX())+(q.getY()-center.getY())*(q.getY()-center.getY()); if(b<radius*radius) return 1; return 0; }};int Circle::numOfCircles=0;int main(){ int cases,num; int x, y, r, px, py; Point aPoint(0,0), *bPoint; Circle aCircle(1,1,1); cin>>cases; cout<<"We have "<<Point::getNumOfPoints()<<" points and "<<Circle::getNumOfCircles()<<" circles now."<<endl; for (int i = 0; i < cases; i++) { cin>>x>>y>>r; bPoint = new Point(x,y); Circle circle(*bPoint, r); cin>>num; for (int j = 0; j < num; j++) { cin>>px>>py; if (circle.pointInCircle(*(new Point(px, py)))) { cout<<"("<<px<<", "<<py<<") is in the circle at ("; cout<<circle.getCenter().getX()<<", "<<circle.getCenter().getY()<<")."<<endl; } else { cout<<"("<<px<<", "<<py<<") is not in the circle at ("; cout<<circle.getCenter().getX()<<", "<<circle.getCenter().getY()<<")."<<endl; } } delete bPoint; } cout<<"We have "<<Point::getNumOfPoints()<<" points, and "<<Circle::getNumOfCircles()<<" circles."<<endl; return 0;}