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  • java——double数据精度问题

    代码:使用BigDecimal来代替double

    public class BigDecimalUtil {
         public static BigDecimal add(double v1,double v2){
             BigDecimal b1 = new BigDecimal(Double.toString(v1));
             BigDecimal b2 = new BigDecimal(Double.toString(v2));
             return b1.add(b2);
         }
         public static BigDecimal sub(double v1,double v2){
             BigDecimal b1 = new BigDecimal(Double.toString(v1));
             BigDecimal b2 = new BigDecimal(Double.toString(v2));
             return b1.subtract(b2);
         }
         public static BigDecimal mul(double v1,double v2){
             BigDecimal b1 = new BigDecimal(Double.toString(v1));
             BigDecimal b2 = new BigDecimal(Double.toString(v2));
             return b1.multiply(b2);
         }
         public static BigDecimal div(double v1,double v2){
             BigDecimal b1 = new BigDecimal(Double.toString(v1));
             BigDecimal b2 = new BigDecimal(Double.toString(v2));
             return b1.divide(b2,2,BigDecimal.ROUND_HALF_UP);//四舍五入,保留2位小数
        }
     }

    double测试示例:

    public class BigDecimalTest{
         @test
         public void test1(){
             System.out.println(0.05+0.01);
             System.out.println(1.0-0.42);
             System.out.println(4.015*100);
             System.out.println(123.3/100);
         }
     }

    //运行结果
    //0.060000000000005
    //0.57000000000000001
    //401.499999999999994
    //1.2329999999999999
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  • 原文地址:https://www.cnblogs.com/Tpf386/p/11175384.html
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