zoukankan      html  css  js  c++  java
  • jQuery火箭图标返回顶部代码

    话不多说,直接上代码:

     1 #include "stdafx.h"
     2 #include<iostream>
     3 using namespace std;
     4 #define MAXSIZE 100
     5 
     6 int F[100];
     7 
     8 //无哨兵顺序查找,a为数组,n为要查找的数组个数,key为要查找的关键字
     9 int Sequential_Search1(int *a, int n, int key)
    10 {
    11     for (int i = 1; i <= n; i++)
    12     {
    13         if (a[i] == key)
    14             return i;
    15     }
    16     return 0;
    17 }
    18 
    19 //有哨兵顺序查找
    20 int Sequential_Search2(int *a, int n, int key)
    21 {
    22     a[0] = key;
    23     int i = n;
    24     while (a[i] != key)
    25     {
    26         i--;
    27     }
    28     return i;
    29 }
    30 
    31 //折半查找
    32 int Binary_Search(int *a, int n, int key)
    33 {
    34     int low, high, mid;
    35     low = 1;                      //定义最底下标为纪录首位
    36     high = n;                     //定义最高下标为记录末尾
    37     while (low <= high)
    38     {
    39         mid = (low + high) / 2;   //折半
    40         if (key < a[mid])         //若查找的值比中值小
    41             high = mid - 1;       //最高下标调整到中位下标小一位
    42         else if (key > a[mid])    //若查找的值比中值打
    43             low = mid + 1;        //最低下标调整到中位下标大一位
    44         else                      
    45         {
    46             return mid;           //若相等则说明mid即为查找到的位置
    47         }
    48     }
    49     return 0;
    50 }
    51 
    52 int main()
    53 {
    54     int a[MAXSIZE + 1], result;
    55     int arr[MAXSIZE] = { 0,1,16,24,35,47,59,62,73,88,99 };
    56 
    57     for (int i = 0; i <= MAXSIZE; i++)
    58     {
    59         a[i] = i;
    60     }
    61     result = Sequential_Search1(a, MAXSIZE, 100);
    62     cout << "Sequential_Search1: " << result << endl;
    63     result = Sequential_Search2(a, MAXSIZE, 1);
    64     cout << "Sequential_Search2: " << result << endl;
    65     result = Binary_Search(arr, 10, 62);
    66     cout << "Binary_Search: " << result << endl;
    67     return 0;
    68 }

    输出如下:

  • 相关阅读:
    索引器
    拆箱,装箱,枚举,结构
    题解报告(CDUT暑期集训——第二场)
    题解报告(CDUT暑期集训——第一场)
    第十一届四川省程序设计竞赛赛后感(电科两日游
    ZOJ4108 Fibonacci in the Pocket
    ZOJ4107 Singing Everywhere
    ZOJ4106 Lucky 7 in the Pocket
    ZOJ4105 Abbreviation
    ZOJ4104 Sequence in the Pocket
  • 原文地址:https://www.cnblogs.com/Trojan00/p/9029813.html
Copyright © 2011-2022 走看看