zoukankan      html  css  js  c++  java
  • [HDU3726]Graph and Queries

    Problem

    给你一张图,点的权值,边和几个操作:
    D x: 删除第x条边
    Q x y: 询问包含x的联通块中权值第y大的权值
    C x y: 将x这个点的权值改为y

    Solution

    一看就要离线处理,把所有操作都倒过来
    然后删除操作变为加边操作

    Notice

    记得: 是改完以后再把点一个一个加入Treap中!!

    Code

    非旋转Treap

    #pragma GCC optimize(2)
    #include<cmath>
    #include<cstdio>
    #include<cstring>
    #include<iostream>
    #include<algorithm>
    using namespace std;
    #define sqz main
    #define ll long long
    #define reg register int
    #define rep(i, a, b) for (reg i = a; i <= b; i++)
    #define per(i, a, b) for (reg i = a; i >= b; i--)
    #define travel(i, u) for (reg i = head[u]; i; i = edge[i].next)
    const int INF = 1e9, N = 3000000;
    const double eps = 1e-6, phi = acos(-1.0);
    ll mod(ll a, ll b) {if (a >= b || a < 0) a %= b; if (a < 0) a += b; return a;}
    ll read(){ ll x = 0; int zf = 1; char ch; while (ch != '-' && (ch < '0' || ch > '9')) ch = getchar();
    if (ch == '-') zf = -1, ch = getchar(); while (ch >= '0' && ch <= '9') x = x * 10 + ch - '0', ch = getchar(); return x * zf;}
    void write(ll y) { if (y < 0) putchar('-'), y = -y; if (y > 9) write(y / 10); putchar(y % 10 + '0');}
    struct Node
    {
        int num1, num2, type;
    }Q[N + 5];
    int point = 0, fa[N + 5], Root[N + 5], T[N + 5], From[N + 5], To[N + 5], Flag[N + 5];
    struct node
    {
        int Val[N + 5], Level[N + 5], Size[N + 5], Son[2][N + 5], Num[N + 5];
        inline void up(int u)
        {
            Size[u] = Size[Son[0][u]] + Size[Son[1][u]] + 1;
        }
        int Newnode(int v)
        {
            int u = ++point;
            Val[u] = v, Level[u] = rand();
            Son[0][u] = Son[1][u] = 0, Size[u] = 1;
            return u;
        }
        int Merge(int X, int Y)
        {
            if (X * Y == 0) return X + Y;
            if (Level[X] < Level[Y])
            {
                Son[1][X] = Merge(Son[1][X], Y);
                up(X); return X;
            }
            else
            {
                Son[0][Y] = Merge(X, Son[0][Y]);
                up(Y); return Y;
            }
        }
        void Split(int u, int t, int &x, int &y)
        {
            if (!u)
    		{
    			x = y = 0;
    			return;
    		}
            if (Val[u] <= t) x = u, Split(Son[1][u], t, Son[1][u], y);
            else y = u, Split(Son[0][u], t, x, Son[0][u]);
            up(u);
        }
        int Find_num(int u, int v)
        {
            if (!u) return 0;
            if (v <= Size[Son[0][u]]) return Find_num(Son[0][u], v);
            else if (v <= Size[Son[0][u]] + 1) return u;
            else return Find_num(Son[1][u], v - Size[Son[0][u]] - 1);
        }
        void Insert(int &u, int v)
        {
        	int t = Newnode(v), x, y;
            Split(u, v, x, y);
        	u = Merge(Merge(x, t), y);
        }
        void Delete(int &u, int v)
        {
            int x, y, z;
            Split(u, v, x, z), Split(x, v - 1, x, y);
            u = Merge(Merge(x, Merge(Son[0][y], Son[1][y])), z);
        }
    }Treap;
    int Find(int x)
    {
        if (fa[x] != x) fa[x] = Find(fa[x]);
        return fa[x];
    }
    void Union(int u, int v)
    {
        if (Treap.Size[Root[u]] < Treap.Size[Root[v]]) swap(u, v);
        while (Treap.Size[Root[v]])
        {
            int t = Treap.Find_num(Root[v], 1);
            Treap.Insert(Root[u], Treap.Val[t]);
            Treap.Delete(Root[v], Treap.Val[t]);
        }
        fa[v] = u;
        Root[v] = 0;
    }
    int sqz()
    {
        int n, m, cas = 0;
        while (~scanf("%d %d", &n, &m) && (n || m))
        {
            point = 0;
            rep(i, 1, n) T[i] = read(), fa[i] = i, Root[i] = 0;
            rep(i, 1, m) From[i] = read(), To[i] = read(), Flag[i] = 0;
            int q = 0; char op[5];
            while (scanf("%s", op) && op[0] != 'E')
            {
                q++;
                if (op[0] == 'D')
                    Q[q].num1 = read(), Flag[Q[q].num1] = 1, Q[q].type = 0;
                else
                {
                    Q[q].num1 = read(), Q[q].num2 = read();
                    if (op[0] == 'C') swap(T[Q[q].num1], Q[q].num2), Q[q].type = 1;
                    else Q[q].type = 2;
                }
            }
            rep(i, 1, n) Treap.Insert(Root[i], T[i]);
            rep(i, 1, m)
                if (!Flag[i])
                {
                    int u = Find(From[i]), v = Find(To[i]);
                    if (u != v) Union(u, v);
                }
            ll ans = 0; int tot = 0;
            per(i, q, 1)
            {
                if (Q[i].type == 0)
                {
                    int u = Find(From[Q[i].num1]), v = Find(To[Q[i].num1]);
                    if (u != v) Union(u, v);
                }
                else if (Q[i].type == 1)
                {
                    int u = Find(Q[i].num1);
                    Treap.Delete(Root[u], T[Q[i].num1]);
                    Treap.Insert(Root[u], Q[i].num2);
                    T[Q[i].num1] = Q[i].num2;
                }
                else
                {
                    int u = Find(Q[i].num1);
                    int t = Treap.Find_num(Root[u], Treap.Size[Root[u]] - Q[i].num2 + 1);
                    if (t != -INF) ans += Treap.Val[t];
                    tot++;
                }
            }
            printf("Case %d: %.6f
    ", ++cas, ans * 1.0 / tot);
        }
        return 0;
    }
    

    旋转Treap

    #include<cmath>
    #include<cstdio>
    #include<cstring>
    #include<iostream>
    #include<algorithm>
    using namespace std;
    #define sqz main
    #define ll long long
    #define reg register int
    #define rep(i, a, b) for (reg i = a; i <= b; i++)
    #define per(i, a, b) for (reg i = a; i >= b; i--)
    #define travel(i, u) for (reg i = head[u]; i; i = edge[i].next)
    const int INF = 1e9, N = 3000000;
    const double eps = 1e-6, phi = acos(-1.0);
    ll mod(ll a, ll b) {if (a >= b || a < 0) a %= b; if (a < 0) a += b; return a;}
    ll read(){ ll x = 0; int zf = 1; char ch; while (ch != '-' && (ch < '0' || ch > '9')) ch = getchar();
    if (ch == '-') zf = -1, ch = getchar(); while (ch >= '0' && ch <= '9') x = x * 10 + ch - '0', ch = getchar(); return x * zf;}
    void write(ll y) { if (y < 0) putchar('-'), y = -y; if (y > 9) write(y / 10); putchar(y % 10 + '0');}
    struct Node
    {
        int num1, num2, type;
    }Q[N + 5];
    int point = 0, fa[N + 5], Root[N + 5], T[N + 5], From[N + 5], To[N + 5], Flag[N + 5];
    struct node
    {
        int Val[N + 5], Level[N + 5], Size[N + 5], Son[2][N + 5], Num[N + 5];
        inline void up(int u)
        {
            Size[u] = Size[Son[0][u]] + Size[Son[1][u]] + Num[u];
        }
        inline void Newnode(int &u, int v)
        {
            u = ++point;
            Level[u] = rand(), Val[u] = v;
            Size[u] = Num[u] = 1, Son[0][u] = Son[1][u] = 0;
        }
        inline void Lturn(int &x)
        {
            int y = Son[1][x]; Son[1][x] = Son[0][y], Son[0][y] = x;
            up(x); up(y); x = y;
        }
        inline void Rturn(int &x)
        {
            int y = Son[0][x]; Son[0][x] = Son[1][y], Son[1][y] = x;
            up(x); up(y); x = y;
        }
    
        void Insert(int &u, int t)
        {
            if (u == 0)
            {
                Newnode(u, t);
                return;
            }
            Size[u]++;
            if (t == Val[u]) Num[u]++;
            else if (t > Val[u])
            {
                Insert(Son[0][u], t);
                if (Level[Son[0][u]] < Level[u]) Rturn(u);
            }
            else if (t < Val[u])
            {
                Insert(Son[1][u], t);
                if (Level[Son[1][u]] < Level[u]) Lturn(u);
            }
        }
        void Delete(int &u, int t)
        {
            if (!u) return;
            if (Val[u] == t)
            {
                if (Num[u] > 1)
                {
                    Num[u]--, Size[u]--;
                    return;
                }
                if (Son[0][u] * Son[1][u] == 0) u = Son[0][u] + Son[1][u];
                else if (Level[Son[0][u]] < Level[Son[1][u]]) Rturn(u), Delete(u, t);
                else Lturn(u), Delete(u, t);
            }
            else if (t > Val[u]) Size[u]--, Delete(Son[0][u], t);
            else Size[u]--, Delete(Son[1][u], t);
        }
    
        int Find_num(int u, int t)
        {
            if (!u) return -INF;
            if (t <= Size[Son[0][u]]) return Find_num(Son[0][u], t);
            else if (t <= Size[Son[0][u]] + Num[u]) return Val[u];
            else return Find_num(Son[1][u], t - Size[Son[0][u]] - Num[u]);
        }
    }Treap;
    int Find(int x)
    {
        if (fa[x] != x) fa[x] = Find(fa[x]);
        return fa[x];
    }
    void Union(int u, int v)
    {
        if (Treap.Size[Root[u]] < Treap.Size[Root[v]]) swap(u, v);
        while (Treap.Size[Root[v]])
        {
            int t = Treap.Find_num(Root[v], 1);
            Treap.Insert(Root[u], t);
            Treap.Delete(Root[v], t);
        }
        fa[v] = u;
        Root[v] = 0;
    }
    int sqz()
    {
        int n, m, cas = 0;
        while (~scanf("%d %d", &n, &m) && (n || m))
        {
            point = 0;
            rep(i, 1, n) T[i] = read(), fa[i] = i, Root[i] = 0;
            rep(i, 1, m) From[i] = read(), To[i] = read(), Flag[i] = 0;
            int q = 0; char op[5];
            while (scanf("%s", op) && op[0] != 'E')
            {
                q++;
                if (op[0] == 'D')
                    Q[q].num1 = read(), Flag[Q[q].num1] = 1, Q[q].type = 0;
                else
                {
                    Q[q].num1 = read(), Q[q].num2 = read();
                    if (op[0] == 'C') swap(T[Q[q].num1], Q[q].num2), Q[q].type = 1;
                    else Q[q].type = 2;
                }
            }
            rep(i, 1, n) Treap.Insert(Root[i], T[i]);
            rep(i, 1, m)
                if (!Flag[i])
                {
                    int u = Find(From[i]), v = Find(To[i]);
                    if (u != v) Union(u, v);
                }
            ll ans = 0; int tot = 0;
            per(i, q, 1)
            {
                if (Q[i].type == 0)
                {
                    int u = Find(From[Q[i].num1]), v = Find(To[Q[i].num1]);
                    if (u != v) Union(u, v);
                }
                else if (Q[i].type == 1)
                {
                    int u = Find(Q[i].num1);
                    Treap.Delete(Root[u], T[Q[i].num1]);
                    Treap.Insert(Root[u], Q[i].num2);
                    T[Q[i].num1] = Q[i].num2;
                }
                else
                {
                    int u = Find(Q[i].num1);
                    int t = Treap.Find_num(Root[u], Q[i].num2);
                    if (t != -INF) ans += t;
                    tot++;
                }
            }
            printf("Case %d: %.6f
    ", ++cas, ans * 1.0 / tot);
        }
        return 0;
    }
    
  • 相关阅读:
    JS jQuery显示隐藏div的几种方法
    PHP 二维数组去重(保留指定键值的同时去除重复的项)
    Java面试题解析(一)
    Java :面向对象
    使用 Spring Framework 时常犯的十大错误
    Spring Boot 面试的十个问题
    《深入理解 Java 内存模型》读书笔记
    Spring Boot 2.0 迁移指南
    MaidSafe区块链项目白皮书解读
    20190712共学问题归纳
  • 原文地址:https://www.cnblogs.com/WizardCowboy/p/7643683.html
Copyright © 2011-2022 走看看