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  • 视频带宽计算Demo

    using System;
    using System.Collections.Generic;
    using System.Linq;
    using System.Text;
    
    namespace DaikuanDemo
    {
        class Program
        {
            static void Main(string[] args)
            {
                var data= bandwidthTesting(1080, 1920, "YCBCR_420", 1.064, 8, 60);
                Console.WriteLine(data);
                Console.ReadLine();
            }
    
            public static double bandwidthTesting(double height, double width, string ChromaSamplingFactor, double PF, double BitsPerPixel, double FrameRate)
            {
    
                double HDMI_H_ACTIVE = width;
                BitsPerPixel = BitsPerPixel * 3;
                /**
                 * 带宽计算公式:
                 * "color_space" : "YCBCR_422"
                 * 视频的总高度*视频的活跃宽度*色度采样因子*PF*像素深度(RGB每个占8,一共是24)*帧率/1 000 000 000
                 * HDMI_V_TOTAL * HDMI_H_ACTIVE * Chroma sampling factor * PF * Bits per pixel * Frame rate / 1 000 000 000
                 */
    
                #region 对采样因子进行处理 retuen lastchromaSamplingFactor --张小墨
                /**
                     * 对色度采样因子进行处理:
                     * 处理思路:
                     * 
                     * 1.定义四个变量,用来存储在横竖方面各自的分子和分母
                     * 2.对ChromaSamplingFactor进行拆分,获取后三位,再将后三位拆成单个的数据
                     * 3.横向的分子是中间的数,分母是第一个数
                     * 4.竖向的,如果不是零,分子是1,分母是2. 如果是0,分子分母都是1
                     * 5.分别对横竖方面的分子分母进行约分
                     * 6.将横竖的分子相加,分母相加,结果进行约分
                     * 7.返回约分后的结果
                     * 
                     */
                //分子
                int line_numerator = 0, vertical_numerator = 0;
                //分母
                int line_denominator = 0, vertical_denominator = 0;
    
                //最终的分子分母
                double last_numerator = 0, last_denominator = 0;
                //YCBCR_422
                var ChromaSamplingNumberstring = ChromaSamplingFactor.Split('_')[1].ToCharArray();
                //取出每个数据
                for (int i = 0; i < ChromaSamplingNumberstring.Length; i++)
                {
                    if (i == 0)
                    {
                        line_denominator = int.Parse(ChromaSamplingNumberstring[i].ToString());
                    }
                    if (i == 1)
                    {
                        line_numerator = int.Parse(ChromaSamplingNumberstring[i].ToString());
                    }
                    if (i == 2)
                    {
                        vertical_numerator = 1;if (int.Parse(ChromaSamplingNumberstring[i].ToString()) != 0)
                        {
                            vertical_denominator = 1;
                        }
                        else
                        {
                            vertical_denominator = 2;
                        }
                    }
                }
                //对行数据进行约分
                if (line_denominator % line_numerator == 0)
                {
                    line_denominator = line_denominator / line_numerator;
                    line_numerator = 1;
    
                }
                //获得最后的分子分母值
                last_denominator = line_denominator + vertical_denominator;
                last_numerator = line_numerator + vertical_numerator;
                double lastchromaSamplingFactor = last_numerator / last_denominator;
                #endregion
    
                #region 计算HDMI_V_TOTA retuen HDMI_V_TOTA --张小墨
                /**
                     * 计算HDMI_V_TOTA:
                     * 计算思路:
                     *1.获取到此种视频的宽高隐藏比例
                     *2.计算例子:x-24%x=1280     (1-0.24)x=1280  x=1280/0.76=1684
                     *
                     */
                double HDMI_V_TOTA = 1080 / (1 - (4.00 / 100));
                #endregion
    
                double bandWidth = HDMI_V_TOTA * HDMI_H_ACTIVE * lastchromaSamplingFactor * PF * BitsPerPixel * FrameRate / 1000000000;
    
    
                return bandWidth;
            }
        }
    }
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  • 原文地址:https://www.cnblogs.com/Xiaomoml/p/13533220.html
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