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  • 洛谷

    https://www.luogu.org/problem/P3391

    使用无旋Treap维护序列,注意的是按顺序插入的序列,所以Insert实际上简化成直接root和Merge合并,但是假如要在序列中插入某个数,则要SplitRank到正确的位置。

    注意SplitRank的写法以及Pushdown的东西。

    #include<bits/stdc++.h>
    using namespace std;
    typedef long long ll;
    #define ls(p) ch[p][0]
    #define rs(p) ch[p][1]
    
    const int MAXN = 200000 + 5;
    int val[MAXN], ch[MAXN][2], rnd[MAXN], siz[MAXN], tot, root;
    bool rev[MAXN];
    
    void Init() {
        root = 0, tot = 0;
    }
    
    inline void PushUp(int p) {
        siz[p] = siz[ls(p)] + siz[rs(p)] + 1;
    }
    
    inline void PushDown(int p) {
        if(rev[p]) {
            swap(ls(p), rs(p));
            if(ls(p))
                rev[ls(p)] ^= 1;
            if(rs(p))
                rev[rs(p)] ^= 1;
            rev[p] = 0;
        }
    }
    
    void SplitRank(int p, int rk, int &x, int &y) {
        if(!p) {
            x = y = 0;
            return;
        }
        PushDown(p);
        if(rk <= siz[ls(p)]) {
            y = p;
            SplitRank(ls(p), rk, x, ls(p));
            PushUp(y);
        } else {
            x = p;
            SplitRank(rs(p), rk - siz[ls(p)] - 1, rs(p), y);
            PushUp(x);
        }
    }
    
    int Merge(int x, int y) {
        if(!x || !y)
            return x | y;
        if(rnd[x] < rnd[y]) {
            PushDown(x);
            rs(x) = Merge(rs(x), y);
            PushUp(x);
            return x;
        } else {
            PushDown(y);
            ls(y) = Merge(x, ls(y));
            PushUp(y);
            return y;
        }
    }
    
    int NewNode(int v) {
        int p = ++tot;
        ch[p][0] = ch[p][1] = 0;
        val[p] = v, rnd[p] = rand();
        siz[p] = 1;
        return p;
    }
    
    void Insert(int &root, int v) {
        root = Merge(root, NewNode(v));
    }
    
    void Reverse(int &root, int l, int r) {
        int x = 0, y = 0, z = 0;
        SplitRank(root, l - 1, x, y);
        SplitRank(y, r + 1 - l, y, z);
        rev[y] ^= 1;
        root = Merge(Merge(x, y), z);
    }
    
    vector<int> ans;
    
    void Show(int p) {
        PushDown(p);
        if(ls(p))
            Show(ls(p));
        ans.push_back(val[p]);
        if(rs(p))
            Show(rs(p));
    }
    
    int d[MAXN], f[MAXN], a[MAXN];
    
    int u2topo[MAXN], cnttopo, topo2u[MAXN];
    
    struct Query {
        int u, k, ans, id;
        bool operator<(const Query& q)const {
            return u2topo[u] < u2topo[q.u];
        }
    } que[MAXN];
    
    struct cmp {
        bool operator()(const Query& q1, const Query& q2)const {
            return q1.id < q2.id;
        }
    };
    
    int que2[MAXN];
    int front, back;
    
    int main() {
    #ifdef Yinku
        freopen("Yinku.in", "r", stdin);
    #endif // Yinku
        int n, q;
        while(~scanf("%d%d", &n, &q)) {
            Init();
            for(int i = 1; i <= n; ++i) {
                Insert(root, i);
            }
            for(int i = 1; i <= q; ++i) {
                int l, r;
                scanf("%d%d", &l, &r);
                Reverse(root, l, r);
            }
            ans.clear();
            Show(root);
            for(int i = 0; i < ans.size(); ++i)
                printf("%d%c", ans[i], " 
    "[i == ans.size() - 1]);
        }
        return 0;
    }
    
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  • 原文地址:https://www.cnblogs.com/Yinku/p/11329436.html
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