zoukankan      html  css  js  c++  java
  • ACM_Power Mouth

    Power Mouth

    Time Limit: 2000/1000ms (Java/Others)

    Problem Description:

    Your task is to calculate the sum of some integers.

    Input:

    The input contains several cases,each case contains an integer N in the first line, and then N lines follow(as a group). Each line starts with a integer M, 
    and then M integers follow in the same line.

    Output:

    For each group of input integers you should output their sum in one line, and you must note that there is a blank line between outputs.
    

    Sample Input:

    It is easy.

    Sample Output:

    It is simple.
    解题思路:题目很简单,输出之间要有一空行,累加m个数并输出即可。
    AC代码:
     1 #include<bits/stdc++.h>
     2 using namespace std;
     3 typedef long long LL;
     4 LL sum,n,m,x;bool flag;
     5 int main(){
     6     while(cin>>n){
     7         flag=false;
     8         while(n--){
     9             cin>>m;sum=0;
    10             if(flag)cout<<endl;//输出之间留一空行,第一次不输出,以后每次都输出空行
    11             while(m--){cin>>x;sum+=x;}
    12             cout<<sum<<endl;
    13             flag=true;
    14         }
    15     }
    16     return 0;
    17 }
  • 相关阅读:
    Django模板系统
    __new__与__init__的区别
    django中models field详解
    快速入门mysql
    jq2
    jq
    前端 js 部分
    前端 js
    前端 css
    前端 table form
  • 原文地址:https://www.cnblogs.com/acgoto/p/9220379.html
Copyright © 2011-2022 走看看