kaggle竞赛全收录app开发规划 标签： apipythonkaggle谷歌翻译网页抓取 2017-04-29 09:31 218人阅读

前言

作为英语不算好; 又想离线看到所有比赛的中文视图; 不得已必须利用爬虫将其下载下来规划到本地;

开发过程

• 1, 要能够离线进行google翻译
• 2, 提供各个详情页重要数据的预览功能
• 3, 利用解析网页工具得到md格式便于预览
• 4, 存储数据到数据库
• 5, 每个竞赛的 kenerl / discuss 高vote 进行爬取记录

目前完成阶段

1, 利用google翻译API模拟浏览器进行翻译

2, 竞赛主页的数据爬取

以上内容花了我整整一天的内容; 写出来简单, 但是每个函数的衔接, bug调试等都要花非常多的精力; 特别是google翻译，网上几乎没有成熟的版本

google翻译代码片

难点介绍

• 1, 每个google翻译的结果通过抓包发现网页都会产生一个 tk; 这个tk是动态的, 这个通过网上的版本利用 pyexecjs 包进行JS代码编译。
• 2, 解析返回结果的 url； 注意是result[4,end]
• 3, open_url 这个比较简单。模拟浏览器也不算难点; 略

# -*- coding: utf-8 -*-

import execjs

class GoogleTranslaterTk():
    def __init__(self):
        self.ctx = execjs.compile("""
        function TL(a) {
        var k = "";
        var b = 406644;
        var b1 = 3293161072;

        var jd = ".";
        var $b = "+-a^+6";
        var Zb = "+-3^+b+-f";

        for (var e = [], f = 0, g = 0; g < a.length; g++) {
            var m = a.charCodeAt(g);
            128 > m ? e[f++] = m : (2048 > m ? e[f++] = m >> 6 | 192 : (55296 == (m & 64512) && g + 1 < a.length && 56320 == (a.charCodeAt(g + 1) & 64512) ? (m = 65536 + ((m & 1023) << 10) + (a.charCodeAt(++g) & 1023),
            e[f++] = m >> 18 | 240,
            e[f++] = m >> 12 & 63 | 128) : e[f++] = m >> 12 | 224,
            e[f++] = m >> 6 & 63 | 128),
            e[f++] = m & 63 | 128)
        }
        a = b;
        for (f = 0; f < e.length; f++) a += e[f],
        a = RL(a, $b);
        a = RL(a, Zb);
        a ^= b1 || 0;
        0 > a && (a = (a & 2147483647) + 2147483648);
        a %= 1E6;
        return a.toString() + jd + (a ^ b)
    };

    function RL(a, b) {
        var t = "a";
        var Yb = "+";
        for (var c = 0; c < b.length - 2; c += 3) {
            var d = b.charAt(c + 2),
            d = d >= t ? d.charCodeAt(0) - 87 : Number(d),
            d = b.charAt(c + 1) == Yb ? a >>> d: a << d;
            a = b.charAt(c) == Yb ? a + d & 4294967295 : a ^ d
        }
        return a
    }
    """)

    def getTk(self, text):
        return self.ctx.call("TL", text)

import urllib.request

def open_url(url): #模拟浏览器解析网页
    headers = {'User-Agent': 'Mozilla/5.0 (Windows NT 6.1; WOW64; rv:23.0) Gecko/20100101 Firefox/23.0'}
    req = urllib.request.Request(url=url, headers=headers)  #python2，urllib.request()
    response = urllib.request.urlopen(req)                  #python2，urllib2.urlopen()
    data = response.read().decode('utf-8')
    return data

def translate(content, tk):
    if len(content) > 4891: ##这里可以用try
        print("翻译长度过长;请注意分割")
        return

    content = urllib.parse.quote(content)

    url = "http://translate.google.cn/translate_a/single?client=t" 
          "&sl=en&tl=zh-CN&hl=zh-CN&dt=at&dt=bd&dt=ex&dt=ld&dt=md&dt=qca" 
          "&dt=rw&dt=rm&dt=ss&dt=t&ie=UTF-8&oe=UTF-8&clearbtn=1&otf=1&pc=1" 
          "&srcrom=0&ssel=0&tsel=0&kc=2&tk={}&q={}".format(tk, content)

    result = open_url(url)

    end = result.find("",")
    if end > 4:
        return result[4:end]

def tranEn2Cn(content):
    js = GoogleTranslaterTk()
    return translate(content, js.getTk(content))

test.py

from translate_goole_sy import tranEn2Cn

print (tranEn2Cn("what are you want to do?!"))
def test2(string):
    ls = string.split('
')
    with open('d:\txt','w+') as f:
        for i in ls:
            if(not None):
                f.writelines(tranEn2Cn(i))
        f.close()

kaggle主页竞赛预览

没什么难点; 主要是按格式解析内容; 花了挺长时间的
- 非贪婪匹配内容; df 数据写入。
- 注意下面的哪些id的内容; 和 columuns 实际是可以动态产生的；

import urllib.request as ur

def open_url(url):
    headers = {'User-Agent': 'Mozilla/5.0 (Windows NT 6.1; WOW64; rv:23.0) Gecko/20100101 Firefox/23.0'}
    req = ur.Request(url=url, headers=headers)  # python2，urllib.request()
    response = ur.urlopen(req)  # python2，urllib2.urlopen()
    return response.read().decode('utf-8')

'''<a class="block-link__anchor" href="/c/"
"intel-mobileodt-cervical-cancer-screening"></a>'''

import pandas as pd
import numpy as np
import re
import json

def demo():
    global n
    regex = '{"competitionId":(.*?),' 
            '"competitionTitle":(.*?),' 
            '"competitionDescription":(.*?),' 
            '"competitionUrl":(.*?),' 
            '"thumbnailImageUrl":(.*?),' 
            '"deadline":(.*?),' 
            '"totalTeams":(.*?),' 
            '"totalKernels":(.*?),' 
            '"rewardQuantity":(.*?),' 
            '"rewardTypeName":(.*?),' 
            '"organizationName":(.*?),' 
            '"organizationUrl":(.*?),' 
            '"hostSegment":(.*?),' 
            '"isLimited":(.*?),' 
            '"isPrivate":(.*?),' 
            '"isInClass":(.*?),' 
            '"userHasEntered":(.*?),' 
            '"rewardDisplay":(.*?)}'

    columns = [ "competitionId","competitionTitle","competitionDescription",
                 "competitionUrl","thumbnailImageUrl","deadline","totalTeams","totalKernels","rewardQuantity",
                "rewardTypeName","organizationName","organizationUrl","hostSegment","isLimited","isPrivate",
                "isInClass","userHasEntered","rewardDisplay"]
    n = len(columns)

    ls = []
    for i_pageNum in np.arange(1,15):
        url2 = "https://www.kaggle.com/competitions?sortBy=deadline&group=all&page=" + 
               str(i_pageNum) + "&segment=allCategories"

        data = open_url(url2)
        lis = re.findall(regex, data)
        for x in lis:
            ls.append(list(x))

    num = 1
    for i in ls:
        print ("------", num,"--------")
        print (i)
        num += 1

    df = pd.DataFrame(ls, columns=columns)
    print (df)
    df.to_csv("C:\Users\actanble\Desktop\de.csv")

if __name__ == "__main__":
    demo()

后记

今天就回家去了, 后面3-4天都没时间弄这个了, 本来说一鼓作气, 两三天弄好的…

实际上, 仔细一想; 官网的数据 排版和观看实际上都是特别方便; 这个数据取下来主要目的是能够利用数据进行一些快速查阅; 这个效用并不是很高。