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  • Ural 1001

    The problem is so easy, that the authors were lazy to write a statement for it!

    Input

    The input stream contains a set of integer numbers Ai (0 ≤ Ai ≤ 1018). The numbers are separated by any number of spaces and line breaks. A size of the input stream does not exceed 256 KB.

    Output

    For each number Ai from the last one till the first one you should output its square root. Each square root should be printed in a separate line with at least four digits after decimal point.

    Sample

    inputoutput
     1427  0   
    
       876652098643267843 
    5276538
      
       
    2297.0716
    936297014.1164
    0.0000
    37.7757
    
    Problem Author: Prepared by Dmitry Kovalioff
    // Ural Problem 1001. Reverse Root
    // Verdict: Accepted  
    // Submission Date: 22:34:56 12 Jan 2014
    // Run Time: 0.328s
    //  
    // 版权所有(C)acutus。(mail: acutus@126.com) 
    //  
    // [解题方法]  
    // 简单题,直接按题意输入输出即可
    // 注意:数组开大点,要使用全局数组
    
    #include<stdio.h>
    
    double a[300000];
    
    void solve(void)
    {
        int i;
        double t;
        i = 0;
        while(scanf("%lf",&t) != EOF) a[i++] = t;
        i--;
        while(i >= 0) {
            printf("%.4lf
    ", sqrt(a[i]));
            i--;
        }
    }
    
    int main(void)
    {
        solve();
        return 0;
    }
    作者:acutus
    本文版权归作者和博客园共有,欢迎转载,但未经作者同意必须保留此段声明,且在文章页面明显位置给出原文连接,否则保留追究法律责任的权利.
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  • 原文地址:https://www.cnblogs.com/acutus/p/3516782.html
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