zoukankan      html  css  js  c++  java
  • HDU 1789 Doing Homework again(贪心)

    题意  某大参加ACM竞赛回来落下很多作业  每个作业都有最后期限   没在最后期限之内做完期末就要扣掉对应的分   求最少扣多少分

    把所有作业按扣分大小从大到小排序  然后就贪阿  能完成前面的就完成前面的  实在不能的就扣分吧~

    #include<cstdio>
    #include<cstring>
    #include<algorithm>
    using namespace std;
    const int N = 1005;
    int dli[N], red[N], k[N], cas, ans, n;
    bool vis[N];
    
    bool cmp (int i, int j)
    {
        return red[i] > red[j];
    }
    
    int main()
    {
        scanf ("%d", &cas);
        while (cas--)
        {
            ans = 0;
            memset (vis, 0, sizeof (vis));
            scanf ("%d", &n);
            for (int i = 1; i <= n; ++i)
                scanf ("%d", &dli[i]), k[i] = i;
            for (int j = 1; j <= n; ++j)
                scanf ("%d", &red[j]);
                
            sort (k + 1, k + n + 1, cmp);
            for (int i = 1, j; i <= n; ++i)
            {
                for (j = dli[k[i]]; j >= 1; --j)
                    if (!vis[j])
                    {
                        vis[j] = 1;
                        break;
                    }
                if (j == 0) ans += red[k[i]];
            }
            printf ("%d
    ", ans);
        }
        return 0;
    }<span style="font-family:Comic Sans MS;">
    </span>

    Doing Homework again


    Problem Description
    Ignatius has just come back school from the 30th ACM/ICPC. Now he has a lot of homework to do. Every teacher gives him a deadline of handing in the homework. If Ignatius hands in the homework after the deadline, the teacher will reduce his score of the final test. And now we assume that doing everyone homework always takes one day. So Ignatius wants you to help him to arrange the order of doing homework to minimize the reduced score.
     

    Input
    The input contains several test cases. The first line of the input is a single integer T that is the number of test cases. T test cases follow.
    Each test case start with a positive integer N(1<=N<=1000) which indicate the number of homework.. Then 2 lines follow. The first line contains N integers that indicate the deadlines of the subjects, and the next line contains N integers that indicate the reduced scores.
     

    Output
    For each test case, you should output the smallest total reduced score, one line per test case.
     

    Sample Input
    3 3 3 3 3 10 5 1 3 1 3 1 6 2 3 7 1 4 6 4 2 4 3 3 2 1 7 6 5 4
     

    Sample Output
    0 3 5
     



  • 相关阅读:
    WPF获取程序版本号(Version)的方法
    WPF中Popup等弹窗的位置不对(偏左或者偏右)
    WPF中Expander与ListBox(ItemsControl)嵌套中的问题
    WPF自定义Button样式(按钮长度随Content长度自适应)
    WPF解决当ScrollViewer中嵌套ItemsControl时,不能使用鼠标来滚动翻页
    WPF中Window的ShowInTaskbar、Owner和Topmost属性
    WPF通过<x:Array>直接为ListBox的ItemsSource赋值
    常用的谓词和逻辑运算符
    利用OVER开窗函数分页
    一个单表查询的示例
  • 原文地址:https://www.cnblogs.com/acvay/p/3947281.html
Copyright © 2011-2022 走看看