A common typing error is to place the hands on the keyboard one row to the right of the correct position. So "Q" is typed as "W" and "J" is typed as "K" and so on. You are to decode a message typed in this manner.
Input consists of several lines of text. Each line may contain digits, spaces, upper case letters (except Q, A, Z), or punctuation shown above [except back-quote (`)]. Keys labelled with words [Tab, BackSp, Control, etc.] are not represented in the input. You are to replace each letter or punction symbol by the one immediately to its left on the QWERTY keyboard shown above. Spaces in the input should be echoed in the output.
Sample Input
O S, GOMR YPFSU/Sample Output
I AM FINE TODAY.思路：先将键盘上的键位存储于字符串中，如果匹配的话就输出前一位，空格和换行照样输出；
#include<iostream>
#include<algorithm>
#include<string>
#include<cmath>
using namespace std;
int main()
{ //先将其存放在字符串中，如果匹配输出前一位
string s="`1234567890-=QWERTYUIOP[]ASDFGHJKL;'ZXCVBNM,./";
char c;
while((c=getchar())!=EOF)
{
if(c==' '||c=='
') //如果有空格和换行，照样输出
cout<<c;
else
{
for(int i=1;i<s.length();i++)
{
if(c==s[i]) //依次寻找匹配
cout<<s[i-1];
}
}
}
return 0;
}