2005

给出一个日期 计算当天是该年的第几天

看了参考答案之后 至于闰年怎么定义 就不讨论了

我的心情是这样的：笨笨笨笨笨

#include <stdio.h>
int leap();
int main()
{
    int year,month,day,sum;
    int leapYear[12] = {31,29,31,30,31,30,31,31,30,31,30,31};
    int NleapYear[12] = {31,28,31,30,31,30,31,31,30,31,30,31};
    while(scanf("%d/%d/%d",&year,&month,&day))
    {
        sum = 0;
        switch (leap(year)) {
        case 0:
            while(month > 1)
            {
                month --;
                sum += NleapYear[month - 1];
            }
            sum += day;
            break;
        default:
            while(month > 1)
            {
                month --;
                sum += leapYear[month - 1];
            }
            sum += day;
            break;
        }
        printf("%d
",sum);
    }

    return 0;
}

int leap(int a)
{
    if(a /400 == 0 || (a /4 == 0 && a /400 != 0))
        return 1;
    else
        return 0;
}

参考c++

#include <math.h>
#include <stdio.h>

#define lev(n) (n % 4 == 0 && (n % 100 != 0 || n % 400 == 0))

int main(void)
{
    int y, m, d, i, s;
    int month[2][13] = {
        {0, 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31},
        {0, 31, 29, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31}
    };

    while (scanf("%d/%d/%d", &y, &m, &d) != EOF)
    {
        for (s = 0, i = 1 ; i < m ; i++)
            s += month[lev(y)][i];
        s += d;
        printf("%d
", s);
    }

    return 0;
}