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  • 图论:树链剖分-边权

    给一个数,边之间有权值,然后两种操作,第一种:求任意两点的权值和,第二,修改树上两点的权值

      1 #include <cstdio>
      2 #include <cstring>
      3 #include <vector>
      4 #include <algorithm>
      5 using namespace std;
      6 #define Del(a,b) memset(a,b,sizeof(a))
      7 const int N = 100005;
      8  
      9 int dep[N],siz[N],fa[N],id[N],son[N],val[N],top[N]; //top 最近的重链父节点
     10 int num,head[N],cnt;
     11 struct Edge
     12 {
     13     int to,next;
     14 };
     15 Edge v[N*2];
     16 struct tree
     17 {
     18     int x,y,val;
     19     void read(){
     20         scanf("%d%d%d",&x,&y,&val);
     21     }
     22 };
     23 void add_Node(int x,int y)
     24 {
     25     v[cnt].to = y;
     26     v[cnt].next = head[x];
     27     head[x] = cnt++;
     28 }
     29 tree e[N];
     30 void dfs1(int u, int f, int d) {
     31     dep[u] = d;
     32     siz[u] = 1;
     33     son[u] = 0;
     34     fa[u] = f;
     35     for(int i = head[u]; i != -1 ;i = v[i].next)
     36     {
     37         int to = v[i].to;
     38         if(to != f)
     39         {
     40             dfs1(to,u,d+1);
     41             siz[u] += siz[to];
     42             if(siz[son[u]] < siz[to])
     43                 son[u] = to;
     44         }
     45     }
     46 }
     47 void dfs2(int u, int tp) {
     48     top[u] = tp;
     49     id[u] = ++num;
     50     if (son[u]) dfs2(son[u], tp);
     51     for(int i = head[u]; i != -1 ;i = v[i].next )
     52     {
     53         int to = v[i].to;
     54         if(to == fa[u] || to == son[u])
     55             continue;
     56         dfs2(to,to);
     57     }
     58 }
     59 #define lson(x) ((x<<1))
     60 #define rson(x) ((x<<1)+1)
     61 struct Tree
     62 {
     63     int l,r,val;
     64 };
     65 Tree tree[4*N];
     66 void pushup(int x) {
     67     tree[x].val = tree[lson(x)].val + tree[rson(x)].val;
     68 }
     69  
     70 void build(int l,int r,int v)
     71 {
     72     tree[v].l=l;
     73     tree[v].r=r;
     74     if(l==r){
     75         tree[v].val = val[l];
     76         return ;
     77     }
     78     int mid=(l+r)>>1;
     79     build(l,mid,v*2);
     80     build(mid+1,r,v*2+1);
     81     pushup(v);
     82 }
     83 void update(int o,int v,int val)  //log(n)
     84 {
     85     if(tree[o].l==tree[o].r)
     86     {
     87         tree[o].val = val;
     88         return ;
     89     }
     90     int mid = (tree[o].l+tree[o].r)/2;
     91     if(v<=mid)
     92         update(o*2,v,val);
     93     else
     94         update(o*2+1,v,val);
     95     pushup(o);
     96 }
     97 int query(int o,int l, int r)
     98 {
     99     if (tree[o].l >= l && tree[o].r <= r) {
    100         return tree[o].val;
    101     }
    102     int mid = (tree[o].l + tree[o].r) / 2;
    103     if(r<=mid)
    104         return query(o+o,l,r);
    105     else if(l>mid)
    106         return query(o+o+1,l,r);
    107     else
    108         return query(o+o,l,mid) + query(o+o+1,mid+1,r);
    109 }
    110  
    111 int Yougth(int u, int v) {
    112     int tp1 = top[u], tp2 = top[v];
    113     int ans = 0;
    114     while (tp1 != tp2) {
    115         if (dep[tp1] < dep[tp2]) {
    116             swap(tp1, tp2);
    117             swap(u, v);
    118         }
    119         ans += query(1,id[tp1], id[u]);
    120         u = fa[tp1];
    121         tp1 = top[u];
    122     }
    123     if (u == v) return ans;
    124     if (dep[u] > dep[v]) swap(u, v);
    125     ans += query(1,id[son[u]], id[v]);
    126     return ans;
    127 }
    128 int main()
    129 {
    130     int n,m,s;
    131     while(~scanf("%d%d%d",&n,&m,&s))
    132     {
    133         cnt = 0;
    134         memset(head,-1,sizeof(head));
    135         for(int i=1;i<n;i++)
    136         {
    137             e[i].read();
    138             add_Node(e[i].x,e[i].y);
    139             add_Node(e[i].y,e[i].x);
    140         }
    141         num = 0;
    142         dfs1(1,0,1);
    143         dfs2(1,1);
    144         for(int i=1;i<n;i++)
    145         {
    146             if(dep[e[i].x] < dep[e[i].y])
    147                 swap(e[i].x,e[i].y);
    148             val[id[e[i].x]] = e[i].val;
    149         }
    150         build(1,num,1);
    151         for(int i=0;i<m;i++)
    152         {
    153             int ok,x,y;
    154             scanf("%d",&ok);
    155             if(ok==0)
    156             {
    157                 scanf("%d",&x);
    158                 printf("%d
    ",Yougth(s,x));
    159                 s = x;
    160             }
    161             else
    162             {
    163                 scanf("%d%d",&x,&y);
    164                 update(1,id[e[x].x],y);
    165             }
    166         }
    167     }
    168     return 0;
    169 }
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  • 原文地址:https://www.cnblogs.com/aininot260/p/9681343.html
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