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  • 【UVa 712】S-Trees

    Time Limit: 3000MS   Memory Limit: Unknown   64bit IO Format: %lld & %llu

     Status

    Description

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    A Strange Tree (S-tree) over the variable set $X_n = {x_1, x_2, dots, x_n}$ is a binary tree representing a Boolean function $f: {0, 1}^n 
ightarrow { 0, 1}$. Each path of the S-tree begins at the root node and consists of n+1 nodes. Each of the S-tree's nodes has a depth, which is the amount of nodes between itself and the root (so the root has depth 0). The nodes with depth less than n are called non-terminal nodes. All non-terminal nodes have two children: the right child and the left child. Each non-terminal node is marked with some variable xi from the variable set Xn. All non-terminal nodes with the same depth are marked with the same variable, and non-terminal nodes with different depth are marked with different variables. So, there is a unique variable xi1corresponding to the root, a unique variable xi2 corresponding to the nodes with depth 1, and so on. The sequence of the variables$x_{i_1}, x_{i_2}, dots, x_{i_n}$ is called the variable ordering. The nodes having depth n are called terminal nodes. They have no children and are marked with either 0 or 1. Note that the variable ordering and the distribution of 0's and 1's on terminal nodes are sufficient to completely describe an S-tree.

    As stated earlier, each S-tree represents a Boolean function f. If you have an S-tree and values for the variables $x_1, x_2, dots, x_n$, then it is quite simple to find out what $f(x_1, x_2, dots, x_n)$ is: start with the root. Now repeat the following: if the node you are at is labelled with a variable xi, then depending on whether the value of the variable is 1 or 0, you go its right or left child, respectively. Once you reach a terminal node, its label gives the value of the function.

    Figure 1: S-trees for the function $x_1 wedge (x_2 vee x_3)$

    On the picture, two S-trees representing the same Boolean function, $f(x_1, x_2, x_3) = x_1 wedge (x_2 vee x_3)$, are shown. For the left tree, the variable ordering is x1x2x3, and for the right tree it is x3x1x2.

    The values of the variables $x_1, x_2, dots, x_n$, are given as a Variable Values Assignment (VVA) 

    egin{displaymath}(x_1 = b_1, x_2 = b_2, dots, x_n = b_n)
end{displaymath}

    with $b_1, b_2, dots, b_n in {0,1}$. For instance, ( x1 = 1, x2 = 1 x3 = 0) would be a valid VVA for n = 3, resulting for the sample function above in the value $f(1, 1, 0) = 1 wedge (1 vee 0) = 1$. The corresponding paths are shown bold in the picture.

    Your task is to write a program which takes an S-tree and some VVAs and computes $f(x_1, x_2, dots, x_n)$ as described above.

    Input 

    The input file contains the description of several S-trees with associated VVAs which you have to process. Each description begins with a line containing a single integer n$1 le n le 7$, the depth of the S-tree. This is followed by a line describing the variable ordering of the S-tree. The format of that line is xi1xi2 ... xin. (There will be exactly n different space-separated strings). So, for n = 3 and the variable ordering x3x1x2, this line would look as follows:

    x3 x1 x2

    In the next line the distribution of 0's and 1's over the terminal nodes is given. There will be exactly 2n characters (each of which can be 0 or 1), followed by the new-line character. The characters are given in the order in which they appear in the S-tree, the first character corresponds to the leftmost terminal node of the S-tree, the last one to its rightmost terminal node.

    The next line contains a single integer m, the number of VVAs, followed by m lines describing them. Each of the m lines contains exactly n characters (each of which can be 0 or 1), followed by a new-line character. Regardless of the variable ordering of the S-tree, the first character always describes the value of x1, the second character describes the value of x2, and so on. So, the line

    110

    corresponds to the VVA ( x1 = 1, x2 = 1, x3 = 0).

    The input is terminated by a test case starting with n = 0. This test case should not be processed.

    Output 

    For each S-tree, output the line `` S-Tree #j:", where j is the number of the S-tree. Then print a line that contains the value of $f(x_1, x_2, dots, x_n)$ for each of the given m VVAs, where f is the function defined by the S-tree.

    Output a blank line after each test case.

    Sample Input 

    3
    x1 x2 x3
    00000111
    4
    000
    010
    111
    110
    3
    x3 x1 x2
    00010011
    4
    000
    010
    111
    110
    0
    

    Sample Output 

    S-Tree #1:
    0011
    
    S-Tree #2:
    0011
    

    Miguel A. Revilla
    2000-02-09
     
    题目看了半天。。。
    搞懂了,其实很简单,用叶子节点构建一棵完全二叉树,然后按查询查找即可。
    #include<cstdio>
    #include<cstring>
    
    using namespace std;
    
    int n, m, kase;
    char s[1 << 8], cmd[1 << 8];
    
    int main()
    {
        kase = 0;
        while (scanf("%d", &n) == 1 && n)
        {
            for (int i = 0; i < n; ++i) scanf("%*s");
            scanf("%s", s);
            scanf("%d", &m);
            printf("S-Tree #%d:
    ", ++kase);
            for (int i = 0; i < m; ++i)
            {
                scanf("%s", cmd);
                int u = 0;
                for (int j = 0; j < n; ++j)
                    if (cmd[j] == '1') u = 2 * u + 1;
                    else u *= 2;
                printf("%c", s[u]);
            }
            printf("
    
    ");
        }
        return 0;
    }
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  • 原文地址:https://www.cnblogs.com/albert7xie/p/4854214.html
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