要求均用C语言实现
1.找出最大长度子字符串（只包含字母），打印并且返回长度。 例如 str = "abc123abcd234abcdefgha324adsdawqdasdaseqqwe345abchded"，最大子字符串是
“adsdawqdasdaseqqwe”
1 int findMaxSubstring(char* str) 2 { 3 int maxLength = 0; 4 int maxStartIndex = 0; 5 int curLength = 0; 6 int curStartIndex = 0; 7 bool isFind = 0; 8 for(unsigned int i = 0;i<strlen(str);i++) 9 { 10 if(str[i] >= 'a' && str[i] <= 'z') 11 { 12 if(isFind == 0) 13 { 14 isFind = 1; 15 curLength = 1; 16 curStartIndex = i; 17 } 18 else 19 { 20 curLength++; 21 } 22 } 23 else if (str[i] < 'a' || str[i] > 'z') 24 { 25 isFind = 0; 26 if(curLength > maxLength) 27 { 28 maxLength = curLength; 29 maxStartIndex = curStartIndex; 30 curLength = 0; 31 } 32 } 33 } 34 char *p = NULL; 35 p = &str[maxStartIndex]; 36 while(*p >= 'a' && *p <= 'z') 37 { 38 putchar(*p); 39 p++; 40 } 41 return maxLength; 42 }
2. 一个四位数，如1024，1004，打印出他们的中文形式，如果一千零二十四，一千零四
这题因为限定了4位数，所以只考虑了4位数的情况，吃点分享一个大小写转换的源码，里面有不限位数的情况，当时调试的很痛苦，思想差不多。
void iConvert(int digit) { char a[5][10] = {"千","百","十","","零"}; char b[11][10] = {"零","一","二","三","四","五","六","七","八","九","十"}; char result[50] = {' '}; int A[4] = {}; for(int i=3;i>=0;i--) { A[i] = digit % 10; digit = int(digit/10); } printf("%d,%d,%d,%d ",A[0],A[1],A[2],A[3]); int foundZero = 0; for(int i = 0 ;i<4;i++) { if(A[i]>0) { strcat(result,b[A[i]]); strcat(result,a[i]); } if(A[i]==0 && foundZero == 0) { if(i!=3)//如果不是最后一位，则不追加零 { strcat(result,a[4]); foundZero = 1; } } } puts(result); }
运行结果：
