X-AA-Challenge X-AA-Challenge-ID X-AA-Challenge-Result

reproduce        https://stackoverflow.com/questions/53434555/python-requests-enable-cookies-javascript

from math import cos, pi, floor

import requests

URL = 'http://www.xxxx'


def parse_challenge(page):
    """
    Parse a challenge given by mmi and mavat's web servers, forcing us to solve
    some math stuff and send the result as a header to actually get the page.
    This logic is pretty much copied from https://github.com/R3dy/jigsaw-rails/blob/master/lib/breakbot.rb
    """
    top = page.split('<script>')[1].split('
')
    challenge = top[1].split(';')[0].split('=')[1]
    challenge_id = top[2].split(';')[0].split('=')[1]
    return {'challenge': challenge, 'challenge_id': challenge_id, 'challenge_result': get_challenge_answer(challenge)}


def get_challenge_answer(challenge):
    """
    Solve the math part of the challenge and get the result
    """
    arr = list(challenge)
    last_digit = int(arr[-1])
    arr.sort()
    min_digit = int(arr[0])
    subvar1 = (2 * int(arr[2])) + int(arr[1])
    subvar2 = str(2 * int(arr[2])) + arr[1]
    power = ((int(arr[0]) * 1) + 2) ** int(arr[1])
    x = (int(challenge) * 3 + subvar1)
    y = cos(pi * subvar1)
    answer = x * y
    answer -= power
    answer += (min_digit - last_digit)
    answer = str(int(floor(answer))) + subvar2
    return answer


def main():
    s = requests.Session()
    r = s.get(URL)

    if 'X-AA-Challenge' in r.text:
        challenge = parse_challenge(r.text)
        r = s.get(URL, headers={
            'X-AA-Challenge': challenge['challenge'],
            'X-AA-Challenge-ID': challenge['challenge_id'],
            'X-AA-Challenge-Result': challenge['challenge_result']
        })

        yum = r.cookies
        r = s.get(URL, cookies=yum)

    print(r.content)