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  • java collections读书笔记(4) stack

    stack,是先进后出的一个堆栈,可是,因为他继承自vector,所以,vector很多功能他都具有。

    stack和vector的关系应该是 has-a,而不是is-a

    简单的操作有,push,top等

    见例子如下:

    import java.util.Stack;
    public class StackExample {
    public static void main (String args[]) {
    Stack s = new Stack();
    s.push("Autumnal Tints");
    s.push("A Week on the Concord and Merrimack Rivers");
    s.push("The Maine Woods");
    // Check out what's next to read
    System.out.println("Next: " + s.peek());
    s.push("Civil Disobedience, Solitude and Life Without Principle");
    // Read a book
    System.out.println(s.pop());
    s.push("Walden");
    s.push("The Natural Man");
    // Find that other book
    int count = s.search("The Maine Woods");
    while (count != −1 && count > 1) {
    s.pop();
    count−;
    }
    // Read a book
    System.out.println(s.pop());
    // Anything left?
    System.out.println(s.empty());
    }
    }

    看看源代码,不复杂:

    public
    class Stack<E> extends Vector<E> {
        /**
         * Creates an empty Stack.
         */
        public Stack() {
        }

        /**
         * Pushes an item onto the top of this stack. This has exactly
         * the same effect as:
         * <blockquote><pre>
         * addElement(item)</pre></blockquote>
         *
         * @param   item   the item to be pushed onto this stack.
         * @return  the <code>item</code> argument.
         * @see     java.util.Vector#addElement
         */
        public E push(E item) {
            addElement(item);

            return item;
        }

        /**
         * Removes the object at the top of this stack and returns that
         * object as the value of this function.
         *
         * @return  The object at the top of this stack (the last item
         *          of the <tt>Vector</tt> object).
         * @throws  EmptyStackException  if this stack is empty.
         */
        public synchronized E pop() {
            E       obj;
            int     len = size();

            obj = peek();
            removeElementAt(len - 1);

            return obj;
        }

        /**
         * Looks at the object at the top of this stack without removing it
         * from the stack.
         *
         * @return  the object at the top of this stack (the last item
         *          of the <tt>Vector</tt> object).
         * @throws  EmptyStackException  if this stack is empty.
         */
        public synchronized E peek() {
            int     len = size();

            if (len == 0)
                throw new EmptyStackException();
            return elementAt(len - 1);
        }

        /**
         * Tests if this stack is empty.
         *
         * @return  <code>true</code> if and only if this stack contains
         *          no items; <code>false</code> otherwise.
         */
        public boolean empty() {
            return size() == 0;
        }

        /**
         * Returns the 1-based position where an object is on this stack.
         * If the object <tt>o</tt> occurs as an item in this stack, this
         * method returns the distance from the top of the stack of the
         * occurrence nearest the top of the stack; the topmost item on the
         * stack is considered to be at distance <tt>1</tt>. The <tt>equals</tt>
         * method is used to compare <tt>o</tt> to the
         * items in this stack.
         *
         * @param   o   the desired object.
         * @return  the 1-based position from the top of the stack where
         *          the object is located; the return value <code>-1</code>
         *          indicates that the object is not on the stack.
         */
        public synchronized int search(Object o) {
            int i = lastIndexOf(o);

            if (i >= 0) {
                return size() - i;
            }
            return -1;
        }

        /** use serialVersionUID from JDK 1.0.2 for interoperability */
        private static final long serialVersionUID = 1224463164541339165L;
    }

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  • 原文地址:https://www.cnblogs.com/aomi/p/3135368.html
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